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Sauron [17]
2 years ago
12

What do chemical and physical change have in common?

Chemistry
1 answer:
gtnhenbr [62]2 years ago
3 0

Explanation:

The similarities between chemical and physical changes include change in state of matter and both process involve change in energy.

Chemical changes of a substance results in the formation of entirely new substances. These changes are not reversible.

Physical changes results in the change of the state of the substance which can be reversed.

However, both chemical and physical changes results in change of state of matter and both process results in change in energy.

Thus, we can conclude that the similarities between chemical and physical changes include change in state of matter and both process involve change in energy.

(it's alre answered but here it again 'NOTE: not my answer')

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Fusion is a type of chemical reaction true or false
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By changing the number of _______ you get the same element that has a different atomic mass. An example of this would be carbon-
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neutrons, isotope

Explanation:

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Which of the following solutions would have the most basic pH? Assume that they are all 0.10 M in acid at 25C. The acid is follo
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Answer:

Explanation:

Given:

Ka of HClO2 = 1.1 × 10-2

Ka of HCHO2 = 1.8 × 10-4

Ka of HCN = 4.9 × 10-10

Ka of HNO2 = 4.6 × 10-4

Ka of HF = 3.5 × 10-4

All at a concentration of 0.1 M

A.

HA --> H+ + A-

Ka = [H+] × [A-]/[HA]

[H+] = [A-] = x

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HClO2 --> ClO2^- + H+

1.1 × 10-2 = x^2/0.1

x = sqrt(1.1 × 10^-3

= 0.033 M

pH = -log[H+]

= 1.48

B.

HA --> H+ + A-

Ka = [H+] × [A-]/[HA]

[H+] = [A-] = x

[HCHO2] = 0.1 M

HCHO2 --> CHO2^- + H+

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x = sqrt(1.8 × 10^-5)

= 0.0042 M

pH = -log[H+]

= 2.37

C.

HA --> H+ + A-

Ka = [H+] × [A-]/[HA]

[H+] = [A-] = x

[HCN] = 0.1 M

HCN --> CN- + H+

4.9 × 10-10 = x^2/0.1

x = sqrt(4.9 × 10-11)

= 0.000007 M

pH = -log[H+]

= 5.16

D.

HA --> H+ + A-

Ka = [H+] × [A-]/[HA]

[H+] = [A-] = x

[HNO2] = 0.1 M

HNO2 --> NO2^- + H+

4.6 × 10-4 = x^2/0.1

x = sqrt(4.6 × 10-5)

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pH = -log[H+]

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E.

HA --> H+ + A-

Ka = [H+] × [A-]/[HA]

[H+] = [A-] = x

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HF --> F- + H+

3.5 × 10-4 = x^2/0.1

x = sqrt(3.5 × 10-5)

= 0.0059 M

pH = -log[H+]

= 2.23

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b) pH = 2.37

c) pH = 5.16

d) pH = 2.17

e) pH = 2.33

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smallest Ka

Highest pH value = 5.16

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