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defon
1 year ago
15

how many bonding pairs and nonbonding pairs of electrons does each nitrogen atom contain?bonding pairs of electrons for nitrogen

atoms:6nonbonding pairs of electrons for nitrogen atom
Chemistry
1 answer:
Len [333]1 year ago
7 0

Five valence electrons are present on each nitrogen atom. Each nitrogen atom contributes three electrons to the triple bond when two nitrogen atoms come together to create the dinitrogen molecule, with the final pair of electrons being a non-bonding lone pair.

<h3>Why Can't Nitrogen Form Four Bonds?</h3>

Nitrogen typically has three bonds, but it has the potential for four. If it happens, a positive charge will be produced. If the atom of nitrogen has a negative charge, it may have two bonds. Oxygen normally has two bonds, but it also has the potential for three. If it has three bonds, there will be a positive charge.

<h3>How many nitrogen atom pairs are free of bonds?</h3>

The triple bonds between the nitrogen atoms hold them together. They each possess one pair of electrons as a result. Therefore, there are a total of two single pairings.

<h3>How many bond pairs does nitrogen have?</h3>

In its no-formal charge state, nitrogen is normally surrounded by three covalent bonds and a lone pair.

To know more about Bonding and Non bonding pair of electron visit:

brainly.com/question/18258856

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This is my first question on Brainly, Can someone explain Molar mass to me? I am not very good with it..
suter [353]
Hey,
A mole is a unit of measure that helps us compare particles of any given substance and its mass. ... The molar mass, also known as molecular weight, is the sum of the total mass in grams of all the atoms that make up a mole of a particular molecule. The unit used to measure is grams per mole.
5 0
3 years ago
A compound is 42.9% C, 2.4% H, 16.7% N, and 38.1% O, by mass. Addition of 6.45 g of this compound to 50.0 mL benzene, lowers the
Romashka [77]

This is an incomplete question, here is a complete question.

A compound is 42.9% C, 2.4% H, 16.7% N and 38.1% O by mass. Addition of 6.45 g of this compound to 50.0 mL benzene, C₆H₆ (d= 0.879 g/mL; Kf= 5.12 degrees Celsius/m), lowers the freezing point from 5.53 to 1.37 degrees Celsius. What is the molecular formula of this compound?

Answer : The molecular of the compound is, C_6H_4N_2O_4

Explanation :

First we have to calculate the mass of benzene.

\text{Mass of benzene}=\text{Density of benzene}\times \text{Volume of benzene}

\text{Mass of benzene}=0.879g/mL\times 50.0mL=43.95g

Now we have to calculate the molar mass of unknown compound.

Given:

Mass of unknown compound (solute) = 6.45 g

Mass of benzene (solvent) = 43.95 g  = 0.04395 kg

Formula used :  

\Delta T_f=K_f\times m\\\\\Delta T_f=K_f\times\frac{\text{Mass of unknown compound}}{\text{Molar mass of unknown compound}\times \text{Mass of benzene in Kg}}

where,

\Delta T_f = change in freezing point  = 5.53-1.37=4.16^oC

\Delta T_s = freezing point of solution

\Delta T^o = freezing point of benzene

Molal-freezing-point-depression constant (K_f) for benzene = 5.12^oC/m

m = molality

Now put all the given values in this formula, we get

4.16^oC=(5.12^oC/m)\times \frac{6.45g}{\text{Molar mass of unknown compound}\times 0.04395kg}

\text{Molar mass of unknown compound}=180.6g/mol

If percentage are given then we are taking total mass is 100 grams.

So, the mass of each element is equal to the percentage given.

Mass of C = 42.9 g

Mass of H = 2.4 g

Mass of N = 16.7 g

Mass of O = 38.1 g

Molar mass of C = 12 g/mole

Molar mass of H = 1 g/mole

Molar mass of N = 14 g/mole

Molar mass of O = 16 g/mole

Step 1 : convert given masses into moles.

Moles of C = \frac{\text{ given mass of C}}{\text{ molar mass of C}}= \frac{42.9g}{12g/mole}=3.575moles

Moles of H = \frac{\text{ given mass of H}}{\text{ molar mass of H}}= \frac{2.4g}{1g/mole}=2.4moles

Moles of N = \frac{\text{ given mass of N}}{\text{ molar mass of N}}= \frac{16.7g}{14g/mole}=1.193moles

Moles of O = \frac{\text{ given mass of O}}{\text{ molar mass of O}}= \frac{38.1g}{16g/mole}=2.381moles

Step 2 : For the mole ratio, divide each value of moles by the smallest number of moles calculated.

For C = \frac{3.575}{1.193}=2.99\approx 3

For H = \frac{2.4}{1.193}=2.01\approx 2

For N = \frac{1.193}{1.193}=1

For O = \frac{2.381}{1.193}=1.99\approx 2

The ratio of C : H : N : O = 3 : 2 : 1 : 2

The mole ratio of the element is represented by subscripts in empirical formula.

The Empirical formula = C_3H_2N_1O_2

The empirical formula weight = 3(12) + 2(1) + 1(14) + 2(16) = 84 gram/eq

Now we have to calculate the molecular formula of the compound.

Formula used :

n=\frac{\text{Molecular formula}}{\text{Empirical formula weight}}

n=\frac{180.6}{84}=2

Molecular formula = (C_3H_2N_1O_2)_n=(C_3H_2N_1O_2)_2=C_6H_4N_2O_4

Therefore, the molecular of the compound is, C_6H_4N_2O_4

3 0
3 years ago
Explain why most metals are malleable and ductile but ionic crystals are not
Dima020 [189]
Throughout the metallic structure allowing the atoms to slide past each other. This sliding is why metals are ductile and malleable. Ioniccompound must break bonds to slide past one another, which causes the ionic material to split and crack.
7 0
3 years ago
Read 2 more answers
Which of the following is not a trait of gases?
iVinArrow [24]
<span>d. tightly packed particles</span>
7 0
2 years ago
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How many atoms of hydrogen are present in 2.92 g of water?
Wittaler [7]
The molecular weight of water is <span>18.01528 g/mol.
So in 2.92 grams there are 2.92/</span>18.01528 = 0.1621 mol of particles.

1 mol contains 6,02214 × 10^<span>23 particles by definition.

So the nr of H2O molecules is </span>0.1621 * 6,02214 × 10^23 = 0,9761 × 10^23.

Every molecule has 2 H atoms, so you have to double that.

2* 0,9761 × 10^23 = 1.952 × 10^23.
3 0
3 years ago
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