Explanation:
Half life of zero order and second order depends on the initial concentration. But as the given reaction slows down as the reaction proceeds, therefore, it must be second order reaction. This is because rate of reaction does not depend upon the initial concentration of the reactant.
a. As it is a second order reaction, therefore, doubling reactant concentration, will increase the rate of reaction 4 times. Therefore, the statement a is wrong.
b. Expression for second order reaction is as follows:
![\frac{1}{[A]} =\frac{1}{[A]_0} +kt](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B%5BA%5D%7D%20%3D%5Cfrac%7B1%7D%7B%5BA%5D_0%7D%20%2Bkt)
the above equation can be written in the form of Y = mx + C
so, the plot between 1/[A] and t is linear. So the statement b is true.
c.
Expression for half life is as follows:
![t_{1/2}=\frac{1}{k[A]_0}](https://tex.z-dn.net/?f=t_%7B1%2F2%7D%3D%5Cfrac%7B1%7D%7Bk%5BA%5D_0%7D)
As half-life is inversely proportional to initial concentration, therefore, increase in concentration will decrease the half life. Therefore statement c is wrong.
d.
Plot between A and t is exponential, therefore there is no constant slope. Therefore, the statement d is wrong
I don’t see nun tho where’s the objects
In order to make the dissolution of the solid compound in water to occur at a faster rate, Samuel could do the following:
1. Break down the solid into tiny particles: breaking down the solid into tiny particles increases the surface area of the solid and thus increase the quantity of the substance that comes in contact with the solvent per time, this leads to a faster dissolution of the solid.
2. Stir the liquid with iron rod: Samuel can increase the dissolution rate of the substance by stirring it continuously with iron rod.
3. Increasing the temperature:Samuel could also increase the rate of dissolution of the substance by increasing the temperature of the water.
Answer:
Mass of water = 6251. 706g or 6.25Kg
Explanation:
Relative humidity = (actual vapor pressure/saturation vapor pressure) * 100%
Actual vapor pressure, Pw = relative humidity * saturation vapor pressure
Pw = 60% * (35.6 *0.001)atm = 0.0216atm
Note: 1mbar = 0.001atm
Using the ideal gas equation: PV=nRT; where P = Pw= 0.02136atm, V= (400
* 1000)dm^3, R= 0.082 atmdm^3/kmol, T= (27+273)K, n = number of moles
Note: 1m^3 = 1000dm^3,R is the molar gas constant.
Making n subject of the formula, n = PV/RT
n= (0.02136 * 400000)/(0.082 * 300) = 347.317 moles
Mass (g) = number of moles (n) * molar mass
molar mass of water=18g
Mass of water = 347.317 * 18 = 6251. 706g or 6.25Kg
