Answer:
The right solution is "0.7107 J/g°C".
Explanation:
The given values are:
Mass,
m = 4.11 g
Temperature,
ΔT = 3.8°C
Heat,
Q = 11.1 J
The specific heat of silicon will be:
⇒ 
On substituting the values, we get
⇒ 
⇒ 
⇒ 
Hey there!
* Converts 1750 dm³ in liters :
1 dm³ = 1 L so 1750 dm³ = 1750 liters
* Convertes 125,000 Pa in atm :
1 Pa = 9.86*10⁻⁶ atm so 9.86*10⁻⁶ / 125,000 => 1.233 atm
* Convertes 127ºC in K :
127 + 273.15 => 400.15 K
R = 0.082 atm.L/mol.K
Finally, it uses an equation of clapeyron :
p * V = n * R * T
1.233 * 1750 = n * 0.082 * 400.15
2157.75 = n * 32.8123
n = 2157.75 / 32.8123
n = 65.76 moles
hope this helps!
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