Answer: The empirical formula for the given compound is 
Explanation : Given,
Mass of O = 0.370 g
Mass of N = 0.130 g
To formulate the empirical formula, we need to follow some steps:
Step 1: Converting the given masses into moles.
Moles of Oxygen = 
Moles of Nitrogen = 
Step 2: Calculating the mole ratio of the given elements.
For the mole ratio, we divide each value of the moles by the smallest number of moles calculated which is 0.00928 moles.
For Oxygen = 
For Nitrogen = 
Step 3: Taking the mole ratio as their subscripts.
The ratio of O : N = 2 : 1
Hence, the empirical formula for the given compound is 
I think it is 3 because Sus wiw word if rn
1.2 moles of (nph4)3po3 is.......159.6 grams
Okay thanks for the update I will give you a call when you get home thanks
C) 3 Moles
This is because of the molecular structure shown in the image