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3 years ago

Question 6

Chemistry

2 answers:

Sholpan [36]3 years ago

8 0

Answer:

C 5.0 m/s²

Explanation:

Given data

Mass (m): 9.0 kg

Force (F): 45 N

A 9.0-kg crate rests on a frictionless surface, thus, the only horizontal force to consider is that of 45 N. We can find the acceleration of the 9.0-kg crate due to the 45 N force using Newton's second law of motion.

F = m × a

a = F/m = 45 N/9.0 kg = 5.0 m/s²

Gnom [1K]3 years ago

5 0

Answer:

the answers 5, also did u finish ur ia yet,

if so you know what to do.

Explanation:

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What is the weight for 2Ba(OH)2

cupoosta [38]

I think its <span>173.34168 g/mol</span>

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4 years ago

How to draw Hess' Cycle for this question ?

NISA [10]

Answer : The standard enthalpy of formation of ethylene is, 51.8 kJ/mole

Explanation :

According to Hess’s law of constant heat summation, the heat absorbed or evolved in a given chemical equation is the same whether the process occurs in one step or several steps.

According to this law, the chemical equation can be treated as ordinary algebraic expression and can be added or subtracted to yield the required equation. That means the enthalpy change of the overall reaction is the sum of the enthalpy changes of the intermediate reactions.

The formation reaction of $C_2H_4$ will be,

$2C(s)+2H_2(g)\rightarrow C_2H_4(g)$ $\Delta H_{formation}=?$

The intermediate balanced chemical reaction will be,

(1) $C_2H_4(g)+3O_2(g)\rightarrow 2CO_2(g)+2H_2O(l)$ $\Delta H_1=-1411kJ/mole$

(2) $C(s)+O_2(g)\rightarrow CO_2(g)$ $\Delta H_2=-393.7kJ/mole$

(3) $H_2(g)+\frac{1}{2}O_2(g)\rightarrow H_2O(l)$ $\Delta H_3=-285.9kJ/mole$

Now we will reverse the reaction 1, multiply reaction 2 and 3 by 2 then adding all the equations, we get :

(1) $2CO_2(g)+2H_2O(l)\rightarrow C_2H_4(g)+3O_2(g)$ $\Delta H_1=+1411kJ/mole$

(2) $2C(s)+2O_2(g)\rightarrow 2CO_2(g)$ $\Delta H_2=2\times (-393.7kJ/mole)=-787.4kJ/mole$

(3) $2H_2(g)+2O_2(g)\rightarrow 2H_2O(l)$ $\Delta H_3=2\times (-285.9kJ/mole)=-571.8kJ/mole$

The expression for enthalpy of formation of $C_2H_4$ will be,

$\Delta H_{formation}=\Delta H_1+\Delta H_2+\Delta H_3$

$\Delta H=(+1411kJ/mole)+(-787.4kJ/mole)+(-571.8kJ/mole)$

$\Delta H=51.8kJ/mole$

Therefore, the standard enthalpy of formation of ethylene is, 51.8 kJ/mole

7 0

3 years ago

I know the answer is 355 bc my teacher gave me the answer but I need to show workand I have no idea how to solve it so somebodyy

omeli [17]

He started off with 32 packs of buns each with 12 buns in it. To start you would do 32 x 12 which gives you 384. After the picnic there were 2 full packages of buns which each have 12 buns in them and another 5 buns. So those 2 packs and the extra would give you 29 buns. You would then take the original amount he started with and take away 29 giving you 355.

5 0

3 years ago

Read 2 more answers

Hexanoic acid, a carboxylic acid, dissolves in 1 M NaOH. Fill in the blank for the missing species:(Structure of Hexanoic acid)

ale4655 [162]

Answer:

Hexanoic acid is water insoluble and sodium hexanoate is water soluble

Explanation:

Hexanoic acid is water insoluble because of presence of long 6 membered non polar and hydrophobic hydrocarbon chain.

When hexanoic acid is treated with NaOH, it is converted to an ionic salt sodium hexanoate which is highly soluble in water because of it's ionic nature.

So, the reaction is given as:

Hexanoic acid + NaOH $\rightarrow$ Sodium hexanoate + water

Reaction in terms of molecular structure has been shown below.

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3 years ago

Will sugar increase or decrease the surface tension of water?

blagie [28]

Answer:

sugars such as dextrose and sucrose increase the surface tension of water. The effect was interpreted as a depletion of the solute molecules from the water-air interface.

7 0

4 years ago