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Nitella [24]
2 years ago
6

A cypress tree is the sprout stage. what would you expect to notice when observing this plant?

Chemistry
1 answer:
Anna007 [38]2 years ago
8 0

Answer:

A  mature stem that has thick bark

Explanation:

i dont know but that is what i put on my test but if you had your awnser right tell me

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Hydrogen chloride (HCl) is added to solid sodium hydroxide (NaOH).
SashulF [63]

Answer:

NaOH and HCl

Explanation:

The reaction of sodium hydroxide, NaOH, with hydrochloric acid, HCl, produces NaCl and water.

5 0
2 years ago
A gas has experienced a small increase in volume but has maintained the same pressure and number of moles. According to the idea
krek1111 [17]

Answer:

If a gas has experienced a small increase in volume but has maintained the same pressure and number of moles, the temperature of the gas will DROP.

Explanation:

According to Boyle’s law of ideal gases, volume and temperature of a gas is inversely related, as long as the pressure is kept constant;

P₁V₁/T₁ = P₂V₂/T₂

Therefore, if the volume of the gas increases, the temperature will definitely decrease due to the inverse relationship. The gas will get cooler.  

Learn More:

For more on Boyle's Law check out;

brainly.com/question/13362447

brainly.com/question/2568628

brainly.com/question/12049334

#LearnWithBrainly

4 0
3 years ago
Name the hydrocarbon...i need help
kondaur [170]

Answer:

The given hydrocarbon is Ethylene Glycol

4 0
3 years ago
Water (10 kg/s) at 1 bar pressure and 50 C is pumped isothermally to 10 bar. What is the pump work? (Use the steam tables.) O -7
11Alexandr11 [23.1K]

Explanation:

For an isothermal process equation will be as follows.

                W = nRT ln\frac{P_{1}}{P_{2}}

It is given that mass is 10 kg/s or 10,000 g/s (as 1 kg = 1000 g). So, calculate number of moles of water as follows.

                    No. of moles = \frac{mass}{\text{molar mass}}

                                           = \frac{10000 g/s}{18 g/mol}

                                           = 555.55 mol/s

                                           = 556 mol/s (approx)

As T = 50^{o}C or (50 + 273.15) K = 323.15 K. Hence, putting the given values into the above formula as follows.

                  W = nRT ln[/tex]\frac{P_{1}}{P_{2}}[/tex]

                      = 556 mol/s \times 8.314 J/ K mol K \times 323.15 K \times ln\frac{1}{10}    

                     = 556 mol/s \times 8.314 J/ K mol K \times 323.15 K \times -2.303    

                     = -3440193.809 J/s

Negative sign shows work is done by the pump. Since, 1 J = 0.001 kJ. Therefore, converting the calculated value into kJ as follows.

                     3440193.809 J/s \times \frac{0.001 kJ}{1 J}

                          = 3440.193 kJ/s

                          = 3451 kJ/s (approx)

Thus, we can conclude that the pump work is 3451 kJ/s.

6 0
3 years ago
What are some chemical properties of noble gasses
Anastaziya [24]
Https://www.thoughtco.com/noble-gases-properties-and-list-of-elements-606656
6 0
2 years ago
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