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Triss [41]
2 years ago
5

g A projectile of mass 3 kg is launched horizontally from an initial height 3 m with an initial velocity 10 m/s. This velocity i

n the x direction is preserved when you ignore air resistance. The projectile still accelerates in the vertical y direction toward the ground, but this is exactly the energy lost from potential energy. Energy is conserved as long as you use the total mechanical energy equation. What is the final kinetic energy as the projectile just reaches the ground
Physics
1 answer:
Ierofanga [76]2 years ago
8 0

Answer:

The kinetic energy at ground will be "238.2 J".

Explanation:

The given values are:

mass,

m = 3 kg

Initial height,

h = 3 m

Initial velocity,

v = 10 m/s

By using the conservation of energy at points A and B,

⇒  E_A=E_B

⇒  mgh+\frac{1}{2}mv^2=k_B

On substituting the values, we get

⇒  3\times 9.8\times 3+\frac{1}{2}\times 3\times (10)^2=k_B

⇒             88.2+0.5\times 3\times 100=k_B

⇒                            88.2+150=k_B

⇒                                    238.2 =k_B

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