Answer:
The answers to your questions are given below.
Explanation:
__ NaBr + CaF₂ —> __ NaF + CaBr₂
The above equation can be balance as follow:
NaBr + CaF₂ —> NaF + CaBr₂
There are 2 atoms of F on the left side and 1 atom on the right side. It can be balance by writing 2 before NaF as shown below:
NaBr + CaF₂ —> 2NaF + CaBr₂
There are 2 atoms of Na on the right side and 1 atom on the left side. It can be balance by writing 2 before NaBr as shown below:
2NaBr + CaF₂ —> 2NaF + CaBr₂
Now, the equation is balanced.
Atom >>>> Reactant >>>> Product
Na >>>>>> 2 >>>>>>>>>>> 2
Br >>>>>>> 2 >>>>>>>>>>> 2
Ca >>>>>> 1 >>>>>>>>>>>> 1
F >>>>>>> 2 >>>>>>>>>>>> 2
Answer:
1.The electonic configuration of elements and their position in the periodic table are related to each other, From the electronic configuration of the elements, we can determine the period and the group to which the element belongs
Let's consider, sodium with atomic number 11 and k, l, and M shells have 2,8,and 1 electrons. since, there are 3 principal energy levels so we concluded sodium belongs to third period M Shell(valance shell) has only 1 electrons. so sodium belongs to group 1.
2. Entire D-block elements are known as Transition Elements.
3. Group 17 is the halogen group.
4. Main group of elements are...... 1,2, and 13 through 18.
5. Group 18 are the noble gas elements .
12. a). Smaller
b). Increases
c). More reactive
d). Softer
7. a). k › Ca › Ge › Br › Kr
b). Ra › Ba › Sr › Ca › Mg › Be
9. a). Ca(calcium) ion is smaller.
b). Cl(chlorine) atom is smaller.
c). Mg(magnesium) atom is smaller.
10. a). F(fluorine)
b). Sr(strontium)
c). Pb(lead)
d). At(Astatine)
To solve this, we should follow order of operations. To start, we should multiply the values inside of the parentheses.
(34.6785*5.39)+435.12
186.917115+435.12
Now, we should add the 2 values we are left with together.
186.917115
<span><u>+435.120000</u>
</span> 622.037115
Using the math above, we can see that this expression is equal to 622.037115.
GG | Gg
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Gg | gg
