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3 years ago

Which newton's laws applies to a slinky? PLEASE HELP !!

2 answers:

7 0

When a Slinky sits atop a staircase, gravity acts on the toy, keeping it still. Knock over the Slinky, and Newton's second law comes into play. As middle school physics class may have taught you, this law states that providing force to an object increases its acceleration.

hopes this helps uh ❣

Natali5045456 [20]3 years ago

3 0

Answer:

We know from Newton's First Law of motion that an object at rest stays at rest unless acted upon by an external force. So in the case of the slinky, that is exactly why the bottom of the slinky does not move.

Explanation:

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Which of the following materials offer the least electrical resistance? Pure water, wood, salt water, glass

Vanyuwa [196]

Salt water offers the least electrical resistance.

<u>Explanation:</u>

Least electrical resistance indicates that any material which readily allows the electric current through itself, and shows more conductivity.

Here pure water doesn't contain any ions, so it is a bad conductor.

Wood and glass are also bad conductors of electricity.

Salt water contains ions, which conducts electricity which means it shows least electrical resistance.

5 0

4 years ago

A round pipe of varying diameter carries petroleum from a wellhead to a refinery. At the wellhead, the pipe's diameter is 50.9 c

seraphim [82]

Answer:

Flow rate 2.34 m3/s

Diameter 0.754 m

Explanation:

Assuming steady flow, the volume flow rate along the pipe will always be constant, and equals to the product of flow speed and cross-section area.

The area at the well head is

$A = \pi r_w^2 = \pi (0.509/2)^2 = 0.203 m^2$

So the volume flow rate along the pipe is

$\dot{V} = Av = 0.203 * 11.5 = 2.34 m^3/s$

We can use the similar logic to find the cross-section area at the refinery

$A_r = \dot{V}/v_r = 2.34 / 5.25 = 0.446 m^2$

The radius of the pipe at the refinery is:

$A_r = \pi r^2$

$r^2 =A_r/\pi = 0.446/\pi = 0.141$

$r = \sqrt{0.141} = 0.377m$

So the diameter is twice the radius = 0.38*2 = 0.754m

6 0

3 years ago

A bicyclist starts at point P and travels around a triangular path that takes her through points Q and R before returning to the

REY [17]

Answer:

Displacement by cyclist is zero.

Explanation:

In the given question bicyclist is travelling in a rectangular track having P , Q and R edges.

The bicyclist starts from P and travel through Q and R and returned to P again.

We need to find its displacement.

We know displacement of a body is its difference between its initial position to final position.

Here in the given question the bicyclist returns to P again.

Therefore, total displacement by bicyclist is zero.

Hence, this is the required solution.

4 0

4 years ago

Why steel ships becomes megnetized as it is constructed

Ksivusya [100]

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3 0

4 years ago

There are four coils of wire being used as electromagnets. They all have the same size and are made up of the same material but

bonufazy [111]

Answer:

The coil with the maximum number of loops will produce the magnetic field with the maximum strength.

Explanation:

The magnetic field produced by a current-carrying coil at a point on the axis which is passing through its center and perpendicular to its plane is given by

$\rm B=\dfrac{\mu_o N I }{2}\ \dfrac{R^2}{(r^2+R^2)^{3/2}}.$

<em>where</em>,

$\mu_o$ = magnetic permeability of the free space.
N = number of loops of the coil.
I = current flowing through the coil.
R = radius of the coil.
r = distance of the point where the magnetic field is to be found from the center of the coil.

Now, it is given that all the four coils have the same size, means same radius R, same material, means same permeability for all the coils, and the same amount of current is passing through all the coils, means same current I.

The magnetic field of all the four coils is differing only due to the number of loops N.

Thus, the coil with the maximum number of loops N will produce the magnetic field with the maximum strength.

4 0

4 years ago