Answer:
"0.60 g" is the appropriate solution.
Explanation:
The given values are:
Volume of base,
= 30 ml
Molarity of base,
= 0.05 m
Molar mass of acid,
= 400 g/mol
As we know,
⇒ 
On substituting the values, we get
⇒ 
⇒ 
⇒ 
hence,
⇒ 
On substituting the values, we get
⇒ 
⇒ 
⇒ 
Pentaarsenic decafluoride
Penta=5
Arsenic=As
Deca=10
Fluoride=F
Drop the -ine and add -ide
To determine the mass of oxygen per gram of sulfur for sulfur dioxide, we simply obtain the ratio of the mass of oxygen and the mass of sulfur produced from the decomposition of sulfur dioxide. All other values given in the problem statement above are just to confuse us that the question is a difficult one. We do as follows:
mass of oxygen per gram sulfur = 3.45 g / 3.46 g
mass of oxygen per gram sulfur = 0.9971 g O2 / g S
Oxidation happens at the anode and reduction happens at the cathode.<span />
Answer:
FALSE
Explanation:
The under-water deep ocean currents that are generated due to the differences in the water density are generally termed as the thermohaline circulation. It is mainly controlled by the two factors namely the temperature and the salinity. The word 'thermohaline' is directly derived from the temperature (thermo) and salinity (haline).
This thermohaline circulation is considered as the oceanic conveyor belt that allows the water to move under the surface of water at certain depths from the equator to the poles and back from the poles to the equator.
Thus, it is directly associated with the density of the water. It has no relation with the wind.
Hence, the above statement is False.
