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shusha [124]
3 years ago
15

What is the concentration that of chloride ions in a .193 m solution of potassium chloride

Chemistry
1 answer:
xenn [34]3 years ago
5 0

Answer:

solution of K3PO4?

1.31 m

2.

Concentration of Chloride Ions in a 0.193m solution of Potassium Chloride is _______.

0.193 m

3.

Concentration of Iodide ions in a 0.193 solution of Barium iodide is _________.

0.386 m

4.

In a Titration of 35.00 mL of 0.737 m H2So4, _______ mL of a 0.827 m KOH solution is required for neautralization.

62.4

5.

Consider the following reactions

AgNo3 ------>

Co(No3) ---->

AgNo3 ---->

Which is the correct order of increasing activity for these metals?

Ag < Co < Zn

6.

There are ______ Mol of bromide ions in 0.500 L of a 0.300M solution of AlBr3

0.450 m

7.

How many grams of Sodium Chloride are there in 550 mL of a 1.90 m aq solution of sodium CL?

6.11 g

8.

The total concentration of ions in a 0.250 M solution of HCL is _______?

0.500 m

9.

How many moles of Co 2+ are present in 0.200 L of a 0.400 M solution of Co I2

0.0800

10.

A Neautralization reaction between an acid and a metal hydroxide produces

Water and a salt

11.

7 Strong Acids

Claire HCl

Brian HBr

invented HI

nutrious HNo3

(3)candy HClO3

(2,4)sold H2So4

(4)profit HClO4

12.

8 strong bases

Lily LiOH Lithium Hydroxide

never NaOH Sodium Hydroxide

knew KOH PossasiumHydroxide

Robert RbOH

could ClOH

bake Ba(OH)2

strawberry Sr(OH)2

cake Ca(OH)2

13.

What are the spectators ions in the reaction between KOH(aq) and HNO(aq)

HF + OH ---> H2O + F-

14.

Combining Aq solution of BaI2 and Na2So4 affords a precipitate of BaSO4

Which Ions is/are spectator ions in the reaction?

Na + and I -

15.

The Spectator ions in the react between aq Hydrochloric acid and Aq Ammonia

Are ________

B. Cl - only

16.

Spectator ions of aq hydrofluoric acid and aq barium hydroxide are _________

D. Ba 2+ only

17.

Spectator ions in reactions

Aq perchloric acid and Aq barium hydroxide are >>>>>>>

ClO 4- and Ba 2+

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Here is a list of some renewable resources, I hope these help answer the question, or help to answer it.

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4 0
3 years ago
Assume that the density and heat of combustion of E85 can be obtained by using 85 % of the values for ethanol and 15 % of the va
Alika [10]

Answer:

87.4 J

Explanation:

The density of the gasoline is 0.70 g/mL, and the density of the ethanol is 0.79 g/mL. The heat combustions (the heat released in a combustion reaction) are 5,400 kJ/mol for gasoline, and 1,370 kJ/mol for ethanol.

For 3.5 L of E85, the volumes of gasoline and ethanol are:

Vgasoline = 0.15 * 3.5 = 0.525 L = 5.25x10⁻⁴ mL

Vethanol= 0.85 * 3.5 = 2.975 L = 2.975x10⁻³ mL

The mass of gasoline and ethanol presented in that sample of E85 is the volume multiplied by the density:

mgasoline = 5.25x10⁻⁴ * 0.70 = 3.675x10⁻⁴ g

methanol = 2.975x10⁻³ * 0.79 = 2.35025x10⁻³ g

The number of moles for each substance is it mass divided by its molar mass. The molar masses are 114 g/mol for gasoline, and 46 g/mol for ethanol:

ngasoline = 3.675x10⁻⁴/114 = 3.224x10⁻⁶ mol

nethanol = 2.35025x10⁻³ /46 = 5.109x10⁻⁵ mol

The energy released is the heat combustion multiplied by the number of moles, so:

Egasoline = 5,400 * 3.224x10⁻⁶ = 0.0174 kJ = 17.4 J

Eethanol = 1,370 * 5.109x10⁻⁵ = 0.07 kJ = 70 J

So, the energy released by the E85 is the sum of the energy released by ethanol and gasoline:

The energy released by E85 = 87.4 J

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