It is a synthesis reaction where two reactants gives one product.
Answer:option D
2Mg + O2 ------> 2 MgO
When light crosses the interface between a medium with higher refractive index and a medium with lower refractive index, there is a maximum value of the angle of incidence after which there is no refraction, but all the light is reflected, and this maximum value is called critical angle.
The critical angle is given by

where n1 is the refractive index of the first medium while n2 is the refractive index of the second medium. In our problem, n1=1.33 and n2=1.58, so the critical angle is
Answer:
Explanation:
First of all, well calculate the spring constant k
K = 2Ei/x^2
Where Ei = initial work required
x = initial stretch length
k = 2×7/0.017^2 = 48443J/m^2
Now work done in stretching it to 5.3cm (1.7 + 3.6) or 0.053m
EF = kx^2/2
48443 × 0.053^2/2 = 68J
Work done in stretching additional 3.6cm is equal to
68J-7J = 61J
The focal length of the converging lens based on the arrow placed 3 centimeters to the left and the imaged formed 3 cm to the right is 1.5 cm.
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Focal length of the converging lens</h3>
The focal length of the converging lens is determined by applying the following converging lens formula.
1/f = 1/v + 1/u
where;
- v is the image distance = 3 cm
- u is the object distance = 3 cm
- f is the focal length = ?
1/f = 1/3 + 1/3
1/f = 2/3
f = 3/2
f = 1.5 cm
Thus, the focal length of the converging lens is 1.5 cm.
Learn more about converging lens here: brainly.com/question/22394546