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galina1969 [7]
3 years ago
6

I need help pls. Solve 1+cos 30º/1-sin 30º. Plz help me​

Physics
1 answer:
Maurinko [17]3 years ago
6 0

Answer:

\huge \boxed{ \boxed{2 +  \sqrt{3}}}

Explanation:

<h3>to understand this</h3><h3>you need to know about:</h3>
  • trigonometry
  • PEMDAS
<h3>given:</h3>
  • \frac{1 +  \cos( {30}^{o} ) }{1 -  \sin( {30}^{o} ) }
<h3>tips and formulas:</h3>
  • cos(30°)=\frac{\sqrt{3}}{2}
  • \sin( {30}^{o} )  =  \frac{1}{2}
<h3>let's solve:</h3>
  1. \sf sustitute \: the \: value \: of \:  \sin( {30}^{o} ) and \cos( {30}^{o} )  \\  \sf \frac{1 +   \frac{ \sqrt{3} }{2}}{1 -  \frac{1}{2} }
  2. \sf simplify :  \\  \frac{ \frac{2 +  \sqrt{3} }{2} }{ \frac{1}{2} }
  3. \sf simplify(fraction) :  \\  \frac{2 +  \sqrt{3} }{2}  \div  \frac{1}{2}  \\ \frac{2 +  \sqrt{3} }{2} \times 2 \\  \therefore 2 +  \sqrt{3}

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Explanation:

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<h3>Focal length of the converging lens</h3>

The focal length of the converging lens is determined by applying the following converging lens formula.

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Learn more about converging lens here: brainly.com/question/22394546

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