Answer:
H' = H/4
Explanation:
By applying the law of conservation of energy to this problem, we know that:
Elastic Potential Energy Stored by Spring = Gravitational Potential Energy of ball
(1/2)kx² = mgH
H = (1/2)kx²/mg -------------- equation (1)
where,
H = Height reached by the ball
x = compression of spring
k = stiffness of spring
m = mass of ball
g = acceleration due to gravity
Now, if we make the compression to half of its value:
x' = x/2
then:
H' = (1/2)k(x/2)²/mg
H' = (1/4)(1/2)kx²/mg
using equation (1), we get:
<u>H' = H/4</u>
Answer:
what is the hunting age? i've never heard of it
Answer:
L2 = 1.1994 m
the length of the pendulum rod when the temperature drops to 0.0°C is 1.1994 m
Explanation:
Given;
Initial length L1 = 1.2m
Initial temperature T1 = 27°C
Final temperature T2 = 0.0°C
Linear expansion coefficient of brass x = 1.9 × 10^-5 /°C
The change i length ∆L;
∆L = L2 - L1
L2 = L1 + ∆L ...........1
∆L = xL1(∆T)
∆L = xL1(T2 - T1) ......2
Substituting the given values into equation 2;
∆L = 1.9 × 10^-5 /°C × 1.2m × (0 - 27)
∆L = 1.9 × 10^-5 /°C × 1.2m × (- 27)
∆L = -6.156 × 10^-4 m
From equation 1;
L2 = L1 + ∆L
Substituting the values;
L2 = 1.2 m + (- 6.156 × 10^-4 m)
L2 = 1.2 m - 6.156 × 10^-4 m
L2 = 1.1993844 m
L2 = 1.1994 m
the length of the pendulum rod when the temperature drops to 0.0°C is 1.1994 m
