Field strength = (15 V) / (4 cm)
Field strength = (15 V) / (0.04 meter)
Field strength = (15/0.04) (volts/meter)
<em>Field strength = 375 volts/meter </em>
The law of conservation of energy is:
-- Energy can't be created or destroyed.
-- Energy can't just appear out of nowhere. If you suddenly have
more energy, then the 'extra' energy had to come from somewhere.
-- Energy can't just disappear. If you suddenly have less energy,
then the 'missing' energy had to go somewhere.
________________________________________
There are also conservation laws for mass and electric charge.
They say exactly the same thing. Just write 'mass' or 'charge'
in the sentences up above, in place of the word 'energy'.
________________________________________
And now I can tell you that the conservation laws for energy and mass
are actually one single law ... the conservation of mass/energy. That's
because we discovered about 100 years ago that mass can convert
into energy, and energy can convert into mass, and it's the total of BOTH
of them that gets conserved (can't be created or destroyed).
How much mass makes how much energy ?
The answer is E = m c² .
Answer:
<em>The distance the car traveled is 21.45 m</em>
Explanation:
<u>Motion With Constant Acceleration
</u>
It occurs when an object changes its velocity at the same rate thus the acceleration is constant.
The relation between the initial and final speeds is:
![v_f=v_o+at\qquad\qquad [1]](https://tex.z-dn.net/?f=v_f%3Dv_o%2Bat%5Cqquad%5Cqquad%20%5B1%5D)
Where:
a = acceleration
vo = initial speed
vf = final speed
t = time
The distance traveled by the object is given by:
![\displaystyle x=v_o.t+\frac{a.t^2}{2}\qquad\qquad [2]](https://tex.z-dn.net/?f=%5Cdisplaystyle%20x%3Dv_o.t%2B%5Cfrac%7Ba.t%5E2%7D%7B2%7D%5Cqquad%5Cqquad%20%5B2%5D)
Solving [1] for a:

Substituting the given data vo=0, vf=6.6 m/s, t=6.5 s:


The distance is now calculated with [2]:

x = 21.45 m
The distance the car traveled is 21.45 m
Answer:
Explanation:
work done=force*displacement
=350N*15m
=5250 joule
It's actually Friction.
I just did the test and got it right.