Answer:
The current would be same in both situation.
Explanation:
Given that,
Current I = 13 A
Number of turns = 23
We need to calculate the induced emf
Using formula of induced emf is
![\epsilon=NA\dfrac{dB}{dt}](https://tex.z-dn.net/?f=%5Cepsilon%3DNA%5Cdfrac%7BdB%7D%7Bdt%7D)
For N = 1
![\epsilon=A\dfrac{dB}{dt}](https://tex.z-dn.net/?f=%5Cepsilon%3DA%5Cdfrac%7BdB%7D%7Bdt%7D)
We need to calculate the current
Using formula of current
![i=\dfrac{\epsilon}{R}](https://tex.z-dn.net/?f=i%3D%5Cdfrac%7B%5Cepsilon%7D%7BR%7D)
Put the value of emf
![i=\dfrac{A\dfrac{dB}{dt}}{R}](https://tex.z-dn.net/?f=i%3D%5Cdfrac%7BA%5Cdfrac%7BdB%7D%7Bdt%7D%7D%7BR%7D)
Now, if the number of turn is 22 , then induced emf would be
![\epsilon'=NA\dfrac{dB}{dt}](https://tex.z-dn.net/?f=%5Cepsilon%27%3DNA%5Cdfrac%7BdB%7D%7Bdt%7D)
Then the current would be
![i'=\dfrac{\epsilon'}{NR}](https://tex.z-dn.net/?f=i%27%3D%5Cdfrac%7B%5Cepsilon%27%7D%7BNR%7D)
![i'=\dfrac{NA\dfrac{dB}{dt}}{NR}](https://tex.z-dn.net/?f=i%27%3D%5Cdfrac%7BNA%5Cdfrac%7BdB%7D%7Bdt%7D%7D%7BNR%7D)
![i'=\dfrac{A\dfrac{dB}{dt}}{R}](https://tex.z-dn.net/?f=i%27%3D%5Cdfrac%7BA%5Cdfrac%7BdB%7D%7Bdt%7D%7D%7BR%7D)
![i'=i](https://tex.z-dn.net/?f=i%27%3Di)
Hence, The current would be same in both situation.
Answer:
Therefore the the highest frequency is 620Hz and lowest frequency is 580Hz
Explanation:
Given data
Source Frequency fs=600Hz
Length r=1.0m
RPM=100 rpm
The speed of the generator is calculated as:
![v_{s}=rw\\v_{s}=r(2\pi f)](https://tex.z-dn.net/?f=v_%7Bs%7D%3Drw%5C%5Cv_%7Bs%7D%3Dr%282%5Cpi%20f%29)
Substitute the given values
![v_{s}=(1.0m)2\pi (\frac{100}{60}rev/s )\\v_{s}=10.47m/s](https://tex.z-dn.net/?f=v_%7Bs%7D%3D%281.0m%292%5Cpi%20%28%5Cfrac%7B100%7D%7B60%7Drev%2Fs%20%29%5C%5Cv_%7Bs%7D%3D10.47m%2Fs)
For approaching generator the frequency is calculated as:
![f_{+}=\frac{f_{s}}{1-\frac{v_{s}}{v} }\\f_{+}=\frac{600Hz}{1-\frac{10.47m/s}{343m/s} } \\f_{+}=620Hz](https://tex.z-dn.net/?f=f_%7B%2B%7D%3D%5Cfrac%7Bf_%7Bs%7D%7D%7B1-%5Cfrac%7Bv_%7Bs%7D%7D%7Bv%7D%20%7D%5C%5Cf_%7B%2B%7D%3D%5Cfrac%7B600Hz%7D%7B1-%5Cfrac%7B10.47m%2Fs%7D%7B343m%2Fs%7D%20%7D%20%5C%5Cf_%7B%2B%7D%3D620Hz)
On the other hand,for the receding generator,Doppler's effect is expressed as:
![f_{-}=\frac{f_{s}}{1+\frac{v_{s}}{v} }\\f_{-}=\frac{600Hz}{1+\frac{10.47m/s}{343m/s} } \\f_{-}=580Hz](https://tex.z-dn.net/?f=f_%7B-%7D%3D%5Cfrac%7Bf_%7Bs%7D%7D%7B1%2B%5Cfrac%7Bv_%7Bs%7D%7D%7Bv%7D%20%7D%5C%5Cf_%7B-%7D%3D%5Cfrac%7B600Hz%7D%7B1%2B%5Cfrac%7B10.47m%2Fs%7D%7B343m%2Fs%7D%20%7D%20%5C%5Cf_%7B-%7D%3D580Hz)
Therefore the the highest frequency is 620Hz and lowest frequency is 580Hz
Answer:
C) Check that the numerical answer is reasonable and the units are what you expected.
Explanation:
The answer is B because if you use process of elimination, you find that A is invalid because Venus is the second planet. C is out because Mars is the 4th planet. D is out because we are nowhere near the Andromeda Galaxy. We are millions of light years away.