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3 years ago

The height of an average adult person is closest to

Physics

2 answers:

Nastasia [14]3 years ago

7 0

6ft for men and 5ft for women

hoa [83]3 years ago

4 0

Need more info:
Gender
Where they live so u can compare to others
Ex. American white male = 5ft 10 in
Ethnicity
Etc.

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An Alaskan rescue plane traveling 42 m/s

Harrizon [31]

Answer:

205 m

Explanation:

We can find the time of flight of the package by considering its vertical motion first. In fact, the vertical position at time t is given by

$y(t) = h + u_y t + \frac{1}{2}gt^2$

where

h = 117 m is the initial height

$u_y = 0$ is the initial vertical velocity

g = -9.8 m/s^2 is the acceleration of gravity

The package reaches the ground when y=0, so substituting this, we find the corresponding time:

$0=h+\frac{1}{2}gt^2\\t=\sqrt{-\frac{2h}{g}}=\sqrt{-\frac{2(117)}{-9.8}}=4.89 s$

Now we can find the horizontal distance travelled by the package by considering the horizontal motion only; so it is given by

$d=v_x t$

where

$v_x = 42 m/s$ is the horizontal velocity of the package (which is constant)

t = 4.89 s

Substituting,

$d=(42)(4.89)=205 m$

So, the package lands 205 m ahead of the point directly below the plane where the package was released.

5 0

3 years ago

A driver in a car,originally moving 12.2 m/s, applies the brakes until the car comes to a stop. The car moves a distance of 36.5

mojhsa [17]

First we have to calculate the acceleration of the car,

$a =\frac{u-v}{t}$

Here, u is initial velocity of the car and its value is given 12.2 m/s and v is final velocity of the car and it comes to stop, so its value zero.

$a=\frac{0-12.2 m/s}{t} =\frac{-12.2 \ m/s}{t}$ .

As during the braking the acceleration is constant, from the kinematic equation,

$s=ut + \frac{1}{2} a t^2$

Here, s is the distance traveled by the car during braking and its value is given 36. 5 m.

Substituting all the values in kinematic equation, we get

$36.5 m =(12.2 m/s) t + \frac{1}{2} (- \frac{12.2 m/s}{t}) t^2 \\\\ 36.5 \ m = (12.2 \ m/s) t -(6.1 \ m/s) t \\\\\ t = \frac{36.5 m}{6.1 m/s} = 5.98 s$

Therefore, car will stop after 5.98 s.

8 0

3 years ago

Need help ???? Only answer if you think you know it

charle [14.2K]

Answer:

I believe it would be Direction B

Explanation:

After passing A, gravity would pull the ball downwards

5 0

3 years ago

An electron is traveling with initial kinetic energy K in a uniform electric field. The electron comes to rest momentarily after

geniusboy [140]

Answer:

$E=\frac{K}{ed}$

Explanation:

We are given that

Initial kinetic energy of an electron=K

Distance=d

Final velocity=v=0

Charge,q=-1e

We have to find the magnitude of electric field.

Work done= $Force\times displacement$

Using the formula

Work done= $qE\times d=-eEd$

Using work energy theorem

Work done=Final K.E-Initial K.E=0-K

Work done=-K

Substitute the values

-K=-eEd

K=eEd

$E=\frac{K}{ed}$

Hence, the magnitude of the electric field= $E=\frac{K}{ed}$

3 0

3 years ago

Un objeto de 1 kg se mueve con una velocidad cambia 10m/s¿se ha realizado trabajo sobre el objeto?

Wewaii [24]

Answer:

I don't speak spanish oso sorry

Explanation:

6 0

3 years ago