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3 years ago

A resistor has a current of 2 amps running

Physics

1 answer:

Annette [7]3 years ago

7 0

Answer:

r=v/I=10/2=5

Explanation:

The answer is 5ohms

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Light travels slowest in high density media, faster in lower density media, and fastest in low density media.

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Answer: C REFRACTION

Explanation: I took the test and got it right lol <3

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3 years ago

A chemical formula that contains a metal and oxygen

Sindrei [870]

Answer:

An Oxide

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4 years ago

At what Fahrenheit temperature are the Celcius and Fahrenheit temperatures numerically the same?

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-40 degrees

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3 years ago

a 2.6 kg block is attached to a horizontal spring that has a spring constant of 126 N/m. At the instant when the displacement of

NeTakaya

Answer:

The acceleration of the object is $5.57\ m/s^2$ .

Explanation:

Given that,

Mass of the block, m = 2.6 kg

Spring constant of the spring, k = 126 N/m

At the instant when the displacement of the spring from its unstained length is 0.115 m. We need to find the acceleration of the object.

When the block is displaced, the force acting on the spring is equal to the force due to its motion. Such as :

$kx=ma$

a is acceleration of the object

$a=\dfrac{kx}{m}\\\\a=\dfrac{126\times 0.115}{2.6}\\\\a=5.57\ m/s^2$

So, the acceleration of the object is $5.57\ m/s^2$ .

8 0

3 years ago

two small spheres spaced 35cm apart have equal charge how many excess elecotrons must be present on each sphere if the magnitude

Maksim231197 [3]

Answer:

Number of electrons, n = 395.47

Explanation:

It is given that,

Force between two spheres, $F=2.2\times 10^{-21}\ N$

Distance between spheres, r = 35 cm = 0.35 m

A force of repulsion is acting on the spheres. It is given by :

$F=k\dfrac{q^2}{r^2}$

$q^2=\dfrac{F.r^2}{k}$

$q^2=\dfrac{2.2\times 10^{-21}\ N\times (0.35\ m)^2}{9\times 10^9\ Nm^2/C^2}$

$q^2=2.99\times 10^{-32}$

$q=1.72\times 10^{-16}\ C$

Let n is the number of electrons on the spheres. So,

q = n e

$n=\dfrac{q}{e}$

$n=\dfrac{1.72\times 10^{-16}}{1.6\times 10^{-19}}$

n = 395.47

So, the the number of excess electrons on the spheres are 395.47. Hence, this is the required solution.

8 0

3 years ago