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SCORPION-xisa [38]
3 years ago
15

Write the isotope notation for an element with 12 protons and 14 neutrons.

Chemistry
1 answer:
PtichkaEL [24]3 years ago
7 0
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In the lab you measure a clean dry crucible and cover to be 24.36 grams. You obtain a 2cm piece of pure magnesium metal. After s
mart [117]

Answer:

1) 0.3g Mg

2)0.5g MgO

3)0.2g O

4)0.01mol Mg & 0.01mol O

5)0.01mol MgO

6) Empirical formula MgO

Explanation:

The mass og Mg is obtained by substracting 24.36g from 24.66g:

24.66 - 24.36 = 0.3g Mg

The ignition of Mg means that it's reacting with oxygen to form an oxide. The increase in the crucible mass after the Mg ignition is due to the addition of oxygen. However, the addition of few drops of water produces a new compound: a hydroxide. According to the oxidation state og Mg (2+), the only magnesium oxide possible is MgO. It happens because the oxidation state of oxygen in oxides is 2-. Which means that just one oxygen atom is required to electrically neutralize one magnesium atom.

We can use a conversion factor to know how much MgO is made from from 0.3 g of Mg:

0.3g Mg*\frac{16gO}{24.3gMg}= 0.2g O

Thereby the mass of the oxide is 0.2g O + 0.3g Mg = 0.5g MgO

We convert the mass of oxygen and magnesium to the respective amounts in moles by using conversion factors:

0.2g O*\frac{1 mol O}{16g O}= 0.01mol O

0.3g Mg*\frac{1mol Mg}{24.3g Mg}= 0.01mol Mg

The moles of MgO can be obtained from:

0.5g MgO*\frac{1mol MgO}{40.3g MgO}= 0.01mol MgO

To obtain the empirical formula, the amount fo moles of each elements must be divided by the smallest one, in this case, 0.01.

The result for both number of  Mg atoms and O atoms is 1. This can be interpreted to mean that there is a Mg atom for each O atom forming the  formula unit of the compound.

The step when water is added to the compound resulting after heating does not affect the calculations necessary for the magnesium oxide.

4 0
3 years ago
A chemistry student needs 60.0 g of 2-ethyltoluene for an experiment. He has available 1.5 kg of a 15.3% w/w solution of 2 ethyl
Mila [183]

Answer:

392 g

Explanation:

The given concentration tells us that<em> in 100 g of solution, there would be 15.3 g of 2-ethyltoluene</em>.

With that in mind we can<u> calculate how many grams of solution would contain 60.0 g of 2-ethyltoluene</u>:

  • Mass of solution * 15.3 / 100 = 60.0 g 2-ethyltoluene
  • Mass of solution = 392 g
8 0
3 years ago
Which of the following has three electrons in its valence shell?
sukhopar [10]

Aluminum has three electrons in its valence shell. if you look at the periodic table, there are numbers at the top. in column 2, the elements have 2 valence electrons, in column 3 they have 3 valence electrons etc.

5 0
3 years ago
If you burn 23.4 g of hydrogen and produce 209 g of water, how much oxygen reacted?
Kitty [74]
The chemical reaction is expressed as:

2H2 + O2 = 2H2O

To determine the amount of oxygen used in the reaction, we use the amount of water produced and the relation of the substances in the reaction we do as follows:

209 g H2O ( 1 mol / 18.02 g ) ( 1 mol O2  / 2 mol H2O ) ( 32 g / 1 mol ) = 185.57 g O2
6 0
3 years ago
What is the kinetic energy of a 100-kg object that is moving with a speed of 12.5 m/s?
miss Akunina [59]
Becasue KE= 1/2 mv squared

KE= 1/2 (100) 12.5 sqaured 
             50           156.25 =

                     7812.5 < is your answer 

Hopefully that makes sense and i did the math right.... 
8 0
3 years ago
Read 2 more answers
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