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andreyandreev [35.5K]
3 years ago
12

Be sure to answer all parts.

Chemistry
1 answer:
tangare [24]3 years ago
7 0

Answer:

(a) cesium bromide (CsBr): 9.15 grams

(b) calcium sulfate (CaSO4):  5.85 grams

(c) sodium phosphate (Na3PO4): 7.05 grams

(d) lithium dichromate (Li2Cr2O7):  9.88 grams

(e) potassium oxalate (K2C2O4):   7.15 grams

Explanation:

<u>(a) cesium bromide (CsBr):</u>

Molar mass of CsBR = 212.81 g/mol

Number of moles = molarity * volume

Number of moles = 0.100 M *0.43 L

Number of moles = 0.043 moles

Mass of CsBr required = moles * Molar mass

Mass of CsBr required = 0.043 moles * 212.81 g/mol

Mass of CsBr required = 9.15 grams

<u>(b) calcium sulfate (CaSO4):</u>

Molar mass of CaSO4 = 136.14 g/mol

Mass of CaSO4 required = moles * Molar mass

Mass of CaSO4 required = 0.043 moles * 136.14 g/mol

Mass of CaSO4 required = 5.85 grams

<u>(c) sodium phosphate (Na3PO4):</u>

Molar mass of Na3PO4 = 163.94 g/mol

Mass of Na3PO4 required = moles * Molar mass

Mass of Na3PO4 required = 0.043 moles * 163.94 g/mol

Mass of Na3PO4 required = 7.05 grams

<u>(d) lithium dichromate (Li2Cr2O7):</u>

Molar mass of Li2Cr2O7 = 229.87 g/mol

Mass of Li2Cr2O7 required = moles * Molar mass

Mass of Li2Cr2O7 required = 0.043 moles * 229.87 g/mol

Mass of Li2Cr2O7 required = 9.88 grams

<u>(e) potassium oxalate (K2C2O4):</u>

Molar mass of K2C2O4 = 166.22 g/mol

Mass of K2C2O4 required = moles * Molar mass

Mass of K2C2O4 required = 0.043 moles * 166.22 g/mol

Mass of K2C2O4 required = 7.15 grams

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The element "X" is "O" (oxygen).

<h3>Calculation:</h3>

Given,

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