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Zigmanuir [339]
3 years ago
7

A 2-day-old newborn male is diagnosed with congenital lactic acidosis because of a defective electron transport protein. This de

ficiency leads to a decrease in the rate at which NADH and FADH2 can be oxidized to produce ATP using oxidative phosphorylation and results in an increase in cytosolic AMP. Under these conditions which glycolytic enzyme would be stimulated?
Chemistry
1 answer:
CaHeK987 [17]3 years ago
5 0

Answer:

Phosphofructokinase-1

Explanation:

Phosphofructokinase-1 is the enzyme which is responsible in controlling glycolysis pathway when the ratio of ATP/AMP is altered.

<u>High levels of AMP and low levels of ATP in the body stimulates activity of the enzyme, Phosphofructokinase-1.</u> Thus, the process of glycolysis is stimulated when the energy charge falls.

The enzyme is inhibited by citrate, PEP and ATP.

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An atom of calcium contains 20 protons how many electrons does it have
harina [27]
20.

Atomic number is equivalent to its protons and electrons. :)
4 0
4 years ago
If the elastic modulus of cobalt (co) is 200 gpa, and the elastic modulus of tungsten carbide (wc) is 700 gpa, calculate the upp
Dmitry_Shevchenko [17]
To determine the upper bond
Ec(u) = EmVm + EpVp
Em is the elastic modulus of cobalt.
E₁ is the elastic modulus of the particulate
Vm is the volume fraction of cobalt
Vp is the volume fraction of particulate
substitute
Ec(u) = 200 (Vm) + 700 (Vp)
To determine the lower bound
Ec (l) = EmEp/VmEp+ VpEm
Substitute
Ec (l) = 200(700)/Vm(700) + Vp (200)
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7 0
4 years ago
Determine the number of hydrogen atoms in the following compound 3Cu(C2H3O2)2
Charra [1.4K]

Answer:5

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6 0
3 years ago
A gaseous fuel mixture stored at 747 mmHg and 298 K contains only methane (CH4) and propane (C3H8). When 11.1 L of this fuel mix
Alisiya [41]

Answer:

M_f=38.8\%

Explanation:

From the question we are told that:

Pressure P=747mmHg

Temperature T=298K

Volume V=11.1

Heat Produced Q=780kJ

Generally the equation for ideal gas is mathematically given by

 PV=nRT

 n= (747/760) *11.1/ (0.0821*298)

 n=0.446mol

Therefore

 x+y=0.446

 x=0.446-y .....1

Since

Heat of combustion of Methane=889 kJ/mol

Heat of combustion of Propane=2220 kJ/mol

Therefore

 x(889) + y(2220) = 760 ...... 2

Comparing Equation 1 and 2 and solving simultaneously

 x=0.446-y .....1

 x(889) + y(2220) = 760 ...... 2

 x=0.173

 y=0.273

Therefore

Mole fraction 0f Methane is mathematically given as

 M_f=\frac{x}{n}*100\%

 M_f=\frac{1.173}{0.446}*100\%

 M_f=38.8\%

7 0
3 years ago
The second stage of photosynthesis produces _____ and _____.
lukranit [14]
The second stage of photosynthesis also called Calvin stage produces glucose

5 0
3 years ago
Read 2 more answers
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