All categories

3 years ago

Which reaction occurs spontaneously

Chemistry

1 answer:

coldgirl [10]3 years ago

5 0

Answer:

Chemical Reaction

Explanation:

You might be interested in

If you subtract an objects starting velocity from its final velocity and divide by the time it took to change velocity, what are

amid [387]

Change in velocity over time is acceleration.

You're finding acceleration .

7 0

3 years ago

Which of the following statements is true? Water (H2O) is an element. A golf ball has a larger volume than a baseball. Most of t

Ipatiy [6.2K]

Most of the substances found on earth are compounds.

(water is made up of 2 elements)

(a baseball is larger than a golf ball by default)

(water has a pH value of 7)

Hope this helps u!

4 0

3 years ago

Read 2 more answers

Drug designers are usually

stiv31 [10]

Scientist and Chemical Engineers

7 0

3 years ago

A. Is lithium (Li) more or less reactive than beryllium (Be)?

damaskus [11]

Answer:

Li is more reactive then Be.

Explanation:

As you go to the farther left and down on the periodic table, the higher that element reactivity is.

5 0

3 years ago

A galvanic cell is set up with two cells containing a cadmium electrode in 0. 250 m cd(no3)2 solution and an iron electrode in 0

Lesechka [4]

The cell potential is 0.01934 V at 25°C.

<h3>What is a galvanic cell?</h3>

A galvanic cell, also known as a voltaic cell, is an electrochemical cell that converts the chemical energy generated by spontaneous redox reactions into electrical energy.

The main components of a galvanic cell are

Anode – Oxidation occurs at the anode

Cathode – Reduction occurs at the cathode

Salt bridge – consists of electrolytes that are needed to complete the circuit in a galvanic cell.

Half-cells – It is important as reduction and oxidation reactions are separated into compartments.

External circuit – it helps in Conducting the flow of electrons between electrodes

At cathode,

$Cd^{2+}(aq) + 2e^-\rightarrow Cd(s)$

At anode,

$Fe(s)+2e^-\rightarrow Fe^{2+}(aq)$

Overall cell reaction

$Fe(s)+Cd^{2+}(aq)\rightarrow Fe^{2+}(aq) + Cd(s)$

$E^o_{cell} = E^o_{cathode} - E^o_{anode}$

= -0.40 -(0.44) = 0.04 V

Nernst equation is given by

$E_{cell} = E^o_{cell} - \frac{2.303RT}{nF} logQ$

At 25°C

$E_{cell} = E^o_{cell} - \frac{0.0592V}{n} logQ$

Here, n = 2 and log Q = log $\frac{0.250}{0.050}$ = 0.699

$E_{cell}$ = 0.01934 V

The cell potential is 0.01934 V at 25°C

Learn more about galvanic cell:

brainly.com/question/13918634

#SPJ4

3 0

1 year ago

Read 2 more answers