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Artyom0805 [142]
4 years ago
6

True or false Are African Grey birds smart .

Physics
2 answers:
Pavel [41]4 years ago
5 0

Answer:

African grey birds  are not only really smart, they are helpful too. They are the first bird species to pass a test that requires them both to understand when another animal needs help and to actually give assistance.

which i think is pretty awesome and when they meet a person they start the boding process and their really sweet and kind at first but anyways

 

its true

notka56 [123]4 years ago
3 0
This is true they are very smart.
You might be interested in
A mass on a string of unknown length oscillates as a pendulum with a period of 1.8 s. What is the period in the following situat
Maslowich

Answer:

Using

Period ( P) is given as

P~√(L/g).

a) since mass has no effect on the period of a pendulum. So, the period will remain 1.8seconds

b) using the formula above ,period varies with the square root of the length. Thus , when the length doubles, the period is multiplied by √2. So, the period is 1.8s*√2 = 2.54s

c) in this case, the period is multiplied by √(1/2).

1.8√(1/2)=1.27s.

d) amplitude of the pendulum doesn't affect the period (unless itsvery high, so, the period is still 1.8s

7 0
4 years ago
When fossil fuels are burnt, what 2 gases are given off?
Mkey [24]
Salutations!

When fossil fuels are burnt, what 2 gases are given off?

When fossil fuels are burnt, the following are one of the two gases when they are given off:

→ Carbon dioxide: Carbon dioxide is a green house gas, and plays a major role in the global warming.

→ Carbon Monoxide: Carbon monoxide is a gas that is dangerous to human beings when released.

Hope I helped (:

Have a great day!
6 0
3 years ago
the resistivity of gold is 2.44×10−8Ω⋅m at room temperature. A gold wire that is 0.9 mm in diameter and 14 cm long carries a cur
cricket20 [7]

Answer:

0.03605 V/m is the electric field in the gold wire.

Explanation:

Resistivity of the gold = \rho = 2.44\times 10^{-8} \Omega.m

Length of the gold wire = L = 14 cm = 0.14 m ( 1 cm = 0.01 m)

Diameter of the wire = d = 0.9 mm

Radius of the wire = r = 0.5 d = 0.5 × 0.9 mm = 0.45 mm = 0.45\times 0.001 m

( 1mm = 0.001 m)

Area of the cross-section = A=\pi r^2=\pi r^(0.45\times 0.001 m)^2

Resistance of the wire = R

Current in the gold wire = 940 mA = 0.940 A ( 1 mA = 0.001 A)

R=\rho\times \frac{L}{A}

V(voltage)=I(current)\times R(Resistance) ( Ohm's law)

\frac{V}{I}=\rho\times \frac{L}{A}

We know, Electric field is given by :

E=\frac{dV}{dr}

E=\frac{V}{L}

E=\frac{V}{L}=\rho\times \frac{I}{A}

E=2.44\times 10^{-8} \Omega.m\times \frac{0.940 A}{\pi r^(0.45\times 0.001 m)^2}=0.03605 V/m

0.03605 V/m is the electric field in the gold wire.

3 0
4 years ago
A magnet of mass 0.20 kg is dropped from rest and falls vertically through a 35.0 cm copper tube. Eddy currents are induced, cau
topjm [15]

Answer:

0.58 J

Explanation:

We know that Total energy is conserved.

Initial Kinetic energy + Initial potential energy = final kinetic energy+ final potential energy + dissipated heat energy

Initial kinetic energy = 0 ( magnet is at rest initially)

Initial Potential energy = m g h = (0.20 kg)(9.81 m/s²)(0.35 m) = 0.69 J

Final kinetic energy = 0.5 m v² = 0.5 ×0.20 kg × 1.10 m/s = 0.11 J

Final potential energy = 0

∴ Dissipated heat energy = (0.69 -0.11) J = 0.58 J

4 0
3 years ago
Two resistors, of R1 = 3.93 Ω and R2 = 5.59 Ω, are connected in series to a battery with an EMF of 24.0 V and negligible interna
son4ous [18]

Answer:

2.521 (A); 14.0924 (V)

Explanation:

more info in the attachment, the answers are marked with red colour.

4 0
3 years ago
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