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3 years ago

True or false Are African Grey birds smart .

Physics

2 answers:

Pavel [41]3 years ago

5 0

Answer:

African grey birds are not only really smart, they are helpful too. They are the first bird species to pass a test that requires them both to understand when another animal needs help and to actually give assistance.

which i think is pretty awesome and when they meet a person they start the boding process and their really sweet and kind at first but anyways

its true

notka56 [123]3 years ago

3 0

This is true they are very smart.

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The top five contributing risk factors to fatal crashes in Texas are: speeding, driving under the influence, failure to control

notsponge [240]

Answer:

I'd assume it'd be distracted driving.

3 0

2 years ago

Read 2 more answers

Two swimmers A and B, of weight 190 lb and 125 lb, respectively, are at diagonally opposite corners of a floating raft when they

Harrizon [31]

Answer:

a) 0.618 ft/s

b) 3.04 ft/s

Explanation:

Givens:

Weight of swimmer A $W_{A}$ = 190 Ib.

Weight of swimmer B $W_{B}$ = 125 Ib.

Weight of the raft $W_{R}$ = 300 Ib.

Swimmer A walks toward swimmer B relative to the raft with a speed

$V_{A/R}$ = 2 ft/s

a) Conservation of linear momentum

$m_{A} v_{A} +m_{B} v_{B} +m_{R} v_{R} =0..........(1)\\v_{A/R}=v_{A} -v_{R}\\\v_{A}=v_{A/R}+v_{R}.................(2)$

Since swimmer B does not move

$v_{B} =v_{R}...............(3)$

Substitute from (2) and (3) into (1)

$m_{A} (v_{A/R} +v_{R} )+m_{B} v_{R} +m_{R} v_{R}=0\\(m_{A}+m_{B}+m_{R})v_{R} =-m_{A}v_{A/R}\\v_{R}=\frac{-m_{A}v_{A/R}}{m_{A}+m_{B}+m_{R}} \\v_{R}=0.618ft/s$

b) if the raft not to move $v_{R}=0$

from (2)

$v_{A} =v_{A/R}$

substitute in (1)

$m_{A} v_{A/R} +m_{B} v_{B}+m_{R} (0)=0\\v_{B}=\frac{W_{A}v_{A/R}}{W_{B}} \\v_{B}=3.04ft/s$

3 0

2 years ago

The index of refraction is based on the ratio of the speed of light in?

Paul [167]

The answer to your question is a vacuum.

6 0

2 years ago

Read 2 more answers

A block of mass M rests on a block of mass M1 which is on a tabletop. A light string passes over a frictionless peg and connects

Pavel [41]

Answer:

M = F/3μ g - M₁/3

Explanation:

To solve this exercise we must use the equilibrium conditions translations

∑ F = 0

In the attachment we can see a free body diagram of each block

Block M (upper)

X axis

fr₁ + F₂ -F = 0

F = fr₁ + F₂ (1)

axis

N₁-W = 0

N₁ = Mg

the friction force has the formula

fr₁ = μ N₁

F = μ Mg + F₂

bottom block

X axis

F₂ - fr₁ - fr₂ = 0

F₂ = fr₁ + fr₂

Y axis

N - W₁ -W = 0

N = g (M + M₁)

we substitute

F₂ = μ Mg + μ (M + M1) g

F₂ = μ g (2M + M₁)

we substitute in 1

F = μ M g + μ g (2M + M₁)

F = μ g (3M + M₁)

we look for mass M

M = (F - μ g M₁)/ 3μ g

M = F/3μ g - M₁/3

the exercise does not have numerical data

4 0

3 years ago

Mitosis is a form of _____ reproduction that produces 2 _____ daughter cells.

defon

Answer:

asexually identically

Explanation:

5 0

2 years ago