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777dan777 [17]
3 years ago
15

Sassdspioewqhfoirwebfoeubeowiwfnbrufjiwrjf

Chemistry
1 answer:
Kruka [31]3 years ago
4 0
Hi thanks for the points
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The standard entropy change of a reaction has a positive value. This reaction results in: Select the correct answer below: a dec
Ira Lisetskai [31]

Explanation:

The standard entropy change of a reaction has a positive value. This reaction results in an increase in entropy.

Positive entropy means the system has increased its degree of disorderness.

5 0
3 years ago
Perform the following calculations and give your answer with the correct number of significant figures:
GarryVolchara [31]
I think this is the answer try it 

172.3995<span>
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4 0
3 years ago
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A 100.0 mL sample of 0.300 M NaOH is mixed with a 100.0 mL sample of 0.300 M HNO3 in a coffee cup calorimeter. If both solutions
Mars2501 [29]

Answer:

Qm  = -55.8Kj/mole

Explanation:

NaOH(aq) + HNO₃(aq) => NaNO₃(aq) + H₂O(l)

Qm = (mc∆T)water /moles acid

Given => 100ml(0.300M) NaOH(aq) + 100ml(0.300M)HNO₃(aq)

=> 0.03mole NaOH(aq) + 0.03mole HNO₃(aq)

=> 0.03mole NaNO₃(aq) + 0.03mole H₂O(l)

ΔH⁰rxn = [(200ml)(1.00cal/g∙°C)(37 – 35)°C]water / 0.03mole HNO₃

= 13,333 cal/mole x 4.184J/cal = 55,787J/mol = 55.8Kj/mole (exothermic)*

Heat of reactions comes from formation of H-Oxy bonds on formation of water of reaction and heats the 200ml of solvent water from 35⁰C to 37⁰C.

4 0
4 years ago
Read 2 more answers
Assume that 1.0 mol of C4H10 is completely burned in excess oxygen to form carbon dioxide and water. How many moles of CO2 would
In-s [12.5K]
You need to first write a chemical equation and balance it
 C₄H₁₀ + O₂ → CO₂ + H₂O
2 C₄H₁₀ + 13 O₂ → 8 CO₂ + 10 H₂O
1.0 moles               X moles
1.0 mol C₄H₁₀ (\frac{8 mol CO₂}{2 mol C₄H₁₀}) = 4 moles of CO₂
7 0
3 years ago
a flask contains 2 gases. the first gas has a pressure of 0.76 atm and the second gas gas a pressure of 4,500 Pa. what is the to
Liula [17]

Answer:

The total pressure is 0,804 atm

Explanation:

We use Dalton's law according to which the sum of the partial pressures is equal to the total pressure of a gas mixture. We convert the pressure in Pascals to atmosphere (it can also be done in reverse):

101300Pa ----1 atm

4500Pa----x= (4500Pa x 1atm)/101300Pa= 0,044 atm

P total= p1 + p2= 0,76 atm + 0,044 atm=0,804 atm

4 0
3 years ago
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