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inna [77]
3 years ago
11

Question 11 of 25

Chemistry
2 answers:
masha68 [24]3 years ago
7 0

Answer:

a.The waves are absorbed or reflected to capture images

Explanation:

How Things Work: TSA scanners use electromagnetic waves for detection. ... These waves are bounced off the body of the person being scanned to create a three-dimensional image on the computer. The backscatter units instead bounce low-level electromagnetic X-rays off the body to create an image on the computer

Olenka [21]3 years ago
6 0

Answer:

A. The waves are absorbed or reflected to capture images or

information

Explanation:

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Two students are planning an investigation to determine if ionic or covalent bonds have stronger intermolecular. They are using
Zarrin [17]

Answer:

conductivity in water/ solid state

Explanation:

becuase, they both dissolve in water the same, therofre it is the least helpful.

4 0
3 years ago
Before the quarry was dug, the land contained more vegetation. What impact has this change most likely
stealth61 [152]

Answer: loss of nutrients

Explanation:

the quarry was dug up and vegetation started dyeing. the quarry was probably rich with nutrients.

7 0
3 years ago
The difference between 24.31 and 18.62
coldgirl [10]

24.31-18.62=5.69

The answer is 5.69

3 0
4 years ago
What is the hybridization of the C atoms in C2Cl4 ?
Dovator [93]

Answer:

sp2

Explanation:

Orbital hybridization is defined as the changes in the orbitals of atoms when they pair with electrons of other atoms to form chemical bonds.

C atoms in C2Cl4 or tetrachloroethene have a total of three bond pairs, two with each chlorine atom and one with other carbon atom and zero lone pairs. Thus, C atoms in C2Cl4 is  sp2 hybridized.

Hence, the correct answer is "sp2".

8 0
3 years ago
Given the two half-reactions, what must be done in the next step before the reaction can be balanced? Au3+ --> Au I- --> I
Artyom0805 [142]

Answer:

The balance equation is

2Au^{+3} + 6I^{-} → 2Au + 3I_{2}

Explanation:

first, we have to make sure that the atoms are balanced

Au^{+3} → Au^{}

2I^{-} → I_{2}

then we proceed to balance charges of each half-reaction

Au^{+3} + 3e^{-} → Au^{}

2I^{-} → I_{2} + 2e^{-}

Now we multiply the half-reactions to match the number of electrons in each one

(Au^{+3} + 3e^{-} → Au^{})x2

            (2I^{-} → I_{2} + 2e^{-})x3

and now we do the sum of the half-reactions

2Au^{+3} + 6e^{-} → 2Au^{}

              6I^{-} → 3I_{2} + 6e^{-}

2Au^{+3} + 6I^{-} → 2Au + 3I_{2}

note: the only atom that needed to be balanced was I

3 0
4 years ago
Read 2 more answers
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