Answer:
The capacitance per unit length is ![5.06\times10^{-11}\ F/m](https://tex.z-dn.net/?f=5.06%5Ctimes10%5E%7B-11%7D%5C%20F%2Fm)
(b) is correct option.
Explanation:
Given that,
Radius a= 2.50 mm
Radius b=7.50 mm
Dielectric constant = 3.68
Potential difference = 120 V
We need to calculate charge per length for the capacitance
Using formula of charge per length
![\lambda=\dfrac{4\pi\epsilon_{0}\Delta V}{2 ln(\dfrac{r_{2}}{r_{1}})}](https://tex.z-dn.net/?f=%5Clambda%3D%5Cdfrac%7B4%5Cpi%5Cepsilon_%7B0%7D%5CDelta%20V%7D%7B2%20ln%28%5Cdfrac%7Br_%7B2%7D%7D%7Br_%7B1%7D%7D%29%7D)
Put the value into the formula
![\lambda=\dfrac{120}{9\times10^{9}\times2 ln(\dfrac{7.50\times10^{-3}}{2.50\times10^{-3}})}](https://tex.z-dn.net/?f=%5Clambda%3D%5Cdfrac%7B120%7D%7B9%5Ctimes10%5E%7B9%7D%5Ctimes2%20ln%28%5Cdfrac%7B7.50%5Ctimes10%5E%7B-3%7D%7D%7B2.50%5Ctimes10%5E%7B-3%7D%7D%29%7D)
![\lambda=6.068\times10^{-9}\ C/m](https://tex.z-dn.net/?f=%5Clambda%3D6.068%5Ctimes10%5E%7B-9%7D%5C%20C%2Fm)
We know that,
![\lambda=\dfrac{Q}{L}](https://tex.z-dn.net/?f=%5Clambda%3D%5Cdfrac%7BQ%7D%7BL%7D)
We need to calculate the capacitance per unit length
Using formula of capacitance per unit length
![C=\dfrac{\dfrac{Q}{L}}{\Delta V}](https://tex.z-dn.net/?f=C%3D%5Cdfrac%7B%5Cdfrac%7BQ%7D%7BL%7D%7D%7B%5CDelta%20V%7D)
![C=\dfrac{6.068\times10^{-9}}{120}](https://tex.z-dn.net/?f=C%3D%5Cdfrac%7B6.068%5Ctimes10%5E%7B-9%7D%7D%7B120%7D)
![C=5.06\times10^{-11}\ F/m](https://tex.z-dn.net/?f=C%3D5.06%5Ctimes10%5E%7B-11%7D%5C%20F%2Fm)
Hence, The capacitance per unit length is ![5.06\times10^{-11}\ F/m](https://tex.z-dn.net/?f=5.06%5Ctimes10%5E%7B-11%7D%5C%20F%2Fm)
Answer:
The angular acceleration is ![\alpha = 3.235 \ rad/s ^2](https://tex.z-dn.net/?f=%5Calpha%20%20%3D%203.235%20%5C%20rad%2Fs%20%5E2)
Explanation:
From the question we are told that
The moment of inertia is ![I = 0.034\ kg \cdot m^2](https://tex.z-dn.net/?f=I%20%20%3D%20%200.034%5C%20kg%20%5Ccdot%20m%5E2)
The net torque is ![\tau = 0.11\ N \cdot m](https://tex.z-dn.net/?f=%5Ctau%20%20%3D%20%200.11%5C%20N%20%5Ccdot%20m)
Generally the net torque is mathematically represented as
![\tau = I * \alpha](https://tex.z-dn.net/?f=%5Ctau%20%3D%20%20I%20%20%2A%20%20%5Calpha)
Where
is the angular acceleration so
![\alpha = \frac{\tau }{I}](https://tex.z-dn.net/?f=%5Calpha%20%20%3D%20%20%5Cfrac%7B%5Ctau%20%7D%7BI%7D)
substituting values
![\alpha = \frac{0.1 1}{ 0.034}](https://tex.z-dn.net/?f=%5Calpha%20%20%3D%20%20%5Cfrac%7B0.1%201%7D%7B%200.034%7D)
![\alpha = 3.235 \ rad/s ^2](https://tex.z-dn.net/?f=%5Calpha%20%20%3D%203.235%20%5C%20rad%2Fs%20%5E2)
Answer:
the mouth I think
Because: the oesophagus is the throat and the mouth is how the food gets to the oesophagus. might be wrong because I'm not sure about the organ part but I'm pretty sure that's all it could be
Answer:
what was the answer
Explanation:
im taking the quiz and could use some help