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patriot [66]
4 years ago
11

If the work done to stretch an ideal spring by 4.0 cm is 6.0 j, what is the spring constant (force constant) of this spring?

Physics
1 answer:
Alisiya [41]4 years ago
4 0

Answer:

The spring constant is 3750 N/m  

Explanation:

Use the following two relationships:

(Work) = (Force) x (Displacement)

(Force) = (Spring constant) x (Displacement)

=>

(Spring constant) = (Force) / (Displacement) = (Work) / (Displacement)^2

(Spring constant) = 6.0 kg.(m^2/s^2) / 0.0016 m^2 = 3750 N/m

The spring constant is 3750 N/m  

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Answer:

3947.6 N

Explanation:

Centripetal Force: This is the force that tend to moves a body towards the center of a circle during circular motion.

The formula for centripetal force is

F = mω²r ........................ Equation 1

Where F = Centripetal force, ω = angular velocity, r = radius.

Where π = 3.1415

Given: m = 4 kg, ω = 0.5 rev/s = (0.5×2π) rad/s = 3.1415 rad/s, r = 100 m.

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F = 4(3.1415)²(100)

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What is the magnite of the net displacement of the mouse?
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Complete Question

A field mouse trying to escape a hawk runs east for 5.0m, darts southeast for 3.0m, then drops 1.0m down a hole into its burrow. What is the magnitude of the net displacement of the mouse?

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Explanation:

From the question we are told that

   The  distance it travels eastward is  x =  5.0 \ m

   The distance it travel towards the southeast  is l  =  3.0\  m

   The distance it travel towards the south is  z =  1 \  m

 

Let x-axis  be east

      y-axis  south

       z-axis into the ground

The angle made between east and south is  \theta  =  45^o

The displacement toward x-axis is

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     y  =  3 *  sin (45)

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        s =  \sqrt{7.12^2 +  2.12^2 +  1^2}

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