A coin slides over a frictionless plane and across an xy coordinate system from the origin to a point with xy coordinates (4.0 m
1 answer:
Answer:
Work done, W = 3.78 Joules
Explanation:
It is given that,
Displacement in x-y coordinate,
Magnitude of force, F = 1.3 N
The force is directed at a counterclockwise angle of 121° from the positive direction of the x axis. Let W is the work done by the force on the coin during the displacement.
Firstly, finding the vector form of force as :
The work done is given by :
W = 3.78 Joules
So, the work done by the force is 3.78 Joules. Hence, this is the required solution.
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Answer
given,
flow from the artery = 3.5 x 10⁻⁶ m³/s
Radius of artery = 5.80 x 10⁻³m
area = π R²
= π x (5.8 x 10⁻³)²
= 1.06 x 10⁻⁴ m²
v = 0.033 m/s
b) new velocity of flow
Radius = R' = R/4
A V = A' V'
R² V = R'² V'
R^2 V = (\dfrac{R}{4})^2 V'
V' = 16 V
V' = 16 x 0.033
V' =0.528 m/s