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pantera1 [17]
3 years ago
6

A coin slides over a frictionless plane and across an xy coordinate system from the origin to a point with xy coordinates (4.0 m

, 5.8 m) while a constant force acts on it. The force has magnitude 1.3 N and is directed at a counterclockwise angle of 121° from the positive direction of the x axis. How much work is done by the force on the coin during the displacement?
I understand that W=Fd and F=MA

W=1.3*d, but Im not quite sure how exactly to find displacement.
Physics
1 answer:
Ilya [14]3 years ago
3 0

Answer:

Work done, W = 3.78 Joules

Explanation:

It is given that,

Displacement in x-y coordinate, d=(4i+5.8j)\ m

Magnitude of force, F = 1.3 N

The force is directed at a counterclockwise angle of 121° from the positive direction of the x axis. Let W is the work done by the force on the coin during the displacement.

Firstly, finding the vector form of force as :

F=1.3\ cos(121)i+1.3\ sin(121)j

F=-0.669i+1.114j

The work done is given by :

W=F.d

W=(-0.669i+1.114j).(4i+5.8j)

W=-0.669\times 4+1.114\times 5.8

W = 3.78 Joules

So, the work done by the force is 3.78 Joules. Hence, this is the required solution.

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LenKa [72]

To solve this problem we need the concepts of Energy fluency and Intensity from chemical elements.

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Then replacing our values we have that

I = 1*10^{-3} * 3.3*10^{10} * e ^{-0.06*1.1} e^{-0.058*7.861}

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3 years ago
What is time and speed and acceleration
Andre45 [30]

Answer:

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Angelina_Jolie [31]
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If the tension in the rope is 160 n, how much work does the rope do on the skier during a forward displacement of 270 m?
Lunna [17]

If the tension in the rope is 160 n, - 43200 J work doen by the rope on the skier during a forward displacement of 270 m.

Given,

Tension force in the rope is (T) = 160 N

Displacement of the skier (S) = 270 m

The displacement takes place in forward direction while the direction of the tension in the rope is opposite to it.

Therefore, work done by the rope on  the skier is,

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Hence work done by the rope is - 43200 J.

Learn more about force problems on

brainly.com/question/26850893

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8 0
2 years ago
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One problem for humans living in outer space is that they are apparently weightless. One way around this problem is to design a
Maurinko [17]

This question is not complete.

The complete question is as follows:

One problem for humans living in outer space is that they are apparently weightless. One way around this problem is to design a space station that spins about its center at a constant rate. This creates “artificial gravity” at the outside rim of the station. (a) If the diameter of the space station is 800 m, how many revolutions per minute are needed for the “artificial gravity” acceleration to be 9.80m/s2?

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T = 2 x 3.14 x √400/9.8

T = 6.28 x 6.39 = 40.13

1/T = 1/40.13 = 0.025 x 60 = 1.5 revolution/minute

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