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MariettaO [177]
10 months ago
15

If a critical mass of fissionable material in a spherical shape is flattened like a hamburger, it will be?

Physics
1 answer:
lawyer [7]10 months ago
8 0

A subcritical state will result by flattening a critical mass of fissionable material into the shape of a hamburger.

To find the answer, we need to know about the critical mass.

<h3>What is critical mass?</h3>
  • A material's nuclear characteristics (particularly, its nuclear fission cross-section), density, shape, enrichment, purity, temperature, and environment all affect its critical mass.
  • A mass of fissile material is considered to be in a critical state when a nuclear chain reaction in the mass is self-sustaining and there is no change in power, temperature, or neutron population.
  • At a specific temperature, a mass might be precisely critical.
  • A subcritical state will result by flattening a critical mass of fissionable material into the shape of a hamburger.
  • The cross sections for fission and absorption grow as the relative neutron velocity drops.

Thus, we can conclude that, a subcritical state will result by flattening a critical mass of fissionable material into the shape of a hamburger.

Learn more about the critical mass here:

brainly.com/question/12545809

#SPJ4

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An ice-making machine inside a refrigerator operates in a Carnot cycle. It takes heat from liquid water at 0.0 ∘C and rejects he
Agata [3.3K]

Answer:

2.36 x 10^6 J

Explanation:

Tc = 0°C = 273 K

TH = 22.5°C = 295.5 K

Qc = heat used to melt the ice

mass of ice, m = 85.7 Kg

Latent heat of fusion, L = 3.34 x 10^5 J/kg

Let Energy supplied is E which is equal to the work done

Qc = m x L = 85.7 x 3.34 x 10^5 =  286.24 x 10^5 J

Use the Carnot's equation

\frac{Q_{H}}{Q_{c}}=\frac{T_{H}}{T_{c}}

Q_{H}=286.24\times 10^{5}\times \frac{295.5}{273}

QH = 309.8 x 10^5 J

W = QH - Qc

W = (309.8 - 286.24) x 10^5

W = 23.56 x 10^5 J

W = 2.36 x 10^6 J

Thus, the energy supplied is 2.36 x 10^6 J.

8 0
3 years ago
A pan hangs from a 50 cm spring. When a 10 kg mass is placed in the pan, it stretches the spring 6 cm. What is a function rule l
MrRissso [65]

Answer:

Explanation:

A Spring stretches / compresses when force is applied on them and they are governed by the Hookes Law which states that the force required to stretch or compress a spring is directly proportional to the distance it is stretched.

F = -kx

F is the force applied and x is the elongation of the spring

k is the spring constant.

negative sign indicates the change in direction from equilibrium position.

In the given question, we dont have force but we know that the pan is hanging. We also know from the Newton's second law of motion that

F=mg

Inserting this into Hooke's Law

mg=-kx

computing it for x,

-x=mg/k

This is the model which will tell the length of the spring against change in the mass located in the pan.

3 0
2 years ago
A uniform string of length 0.50 m is fixed at both ends. Find the
kozerog [31]

Answer:

configuration of string:

Node - Antinode - Node    or N-A-N

This is 1/2 wavelength since a full wavelength is N-A-N-A-N

f (fundamental) = V / wavelength

F0 = 300 m/s / 1 m = 100 / sec

F1 = 300 m/s / .5 m = 600 / sec

Each increase is a multiple of the fundamental since the wavelength

increases by 1/2 wavelength to keep nodes at both ends of the string

4 0
2 years ago
A long, nonconducting cylinder (radius = 6.0 mm) has a nonuniform volume charge density given by αr2, where α = 6.2 mC/m5 and r
erastovalidia [21]

Answer: 2.80 N/C

Explanation: In order to calculate the electric firld inside the solid cylinder

non conductor we have to use the Gaussian law,

∫E.ds=Q inside/ε0

E*2πrL=ρ Volume of the Gaussian surface/ε0

E*2πrL= a*r^2 π* r^2* L/ε0

E=a*r^3/(2*ε0)

E=6.2 * (0.002)^3/ (2*8.85*10^-12)= 2.80 N/C

5 0
3 years ago
How much heat is released when 30 g of water at 96°C cools to 25°C?The specific heat of water is 1 cal/gºC.
Blababa [14]
2130 cal is how much is released qhen 30 g of water at
3 0
2 years ago
Read 2 more answers
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