Answer:
Explanation:
capacitance of capacitor
= ε₀ A / d , A is area of plate , d is plate separation
= (8.85 x10⁻¹² x 1.7² x 10⁻⁴) /( .35 x 10⁻³ )
= 73 x 10⁻¹³ F
Charge = 4.5 x 10⁻⁷
voltage between the plates,
Δ V = charge / capacitance
= 4.5 x 10⁻⁷ / 73 x 10⁻¹³
= .0616 x 10⁶
= 616 x 10² V
To make the vottage double , we will reduce capacitance to half .
To reduce capacitance half we will increase plate distance to double.
new plate distance
= 1.7 x 2
= 3.4 cm
<h3><u>Answer;</u></h3>
<em>-Rubidium (Rb)</em>
<h3><u>Explanation;</u></h3>
- <em><u>Alkali metals are group 1 elements, </u></em>they have a valency of 1 and react by loosing electrons to attain a stable configuration.
- <em><u>The reactivity of alkali metals increases down the group, this is due to the increase in the number of energy levels</u></em> which makes it easier for the valence electrons to be lost.
- Therefore, in our case,<em><u> rubidium will be the most reactive as it contains more number of energy levels</u></em>, therefore it will loose valence electron more easily compared to the other alkali metals above it in the group.
Answer: clean out the wound before putting a bandage on
Explanation:
Answer:
where is the picture of star