Light enter the container of the liquid at the angle 37° to the normal refraction beam makes an angle of 27° with the normal. Ca
lculate the index of the liquid
1 answer:
Answer: 1.33
Explanation:
We would apply Snell's law which is expressed as
niSinθi = nrSinθr
where
θi = angle of incidence
θr = angle of refraction
ni = index of refraction of the incident medium(air)
nr = index of refraction of the refractive medium(liquid in this case)
From the information given,
ni = 1(index for air)
θi = 37
θr = 27
By substituting these values into the formula, we have
1 * sin37 = nr * sin27
nr = sin37/sin27
nr = 1.33
The index of the liquid is 1.33
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