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The volume of SO2 produced at 325k is calculated as below
calculate the moles of SO2 produced which is calculated as follows
write the reacting equation
K2SO3 +2 HCl = 2KCl +H2O+ SO2
find the moles of HCl used
=mass/molar mass = 15g/ 36.5 g/mol =0.411 moles
by use of mole ratio between HCl to SO2 which is 2:1 the moles of SO2 is therefore = 0.411 /2 =0.206 moles of SO2
use the idea gas equation to calculate the volume SO2
that is V=nRT/P
where n=0.206 moles
R(gas constant) = 0.082 L.atm/ mol.k
T=325 K
P=1.35 atm
V=(0.206 moles x 0.082 L.atm/mol.k x325 k)/1.35 atm = 4.07 L of SO2
Answer:
A.
Explanation:
In the case of a seesaw, the object at the top is the effort and the object at the bottom is the load.
Answer:
The pressure is 58.75 atm.
Explanation:
From Vanderwaal's equation,
P = nRT/(V-nb) - n^2a/V^2
n is the number of moles of SO2 = mass/MW = 500/64 = 7.81 mol
R is gas constant = 0.0821 L.atm/mol.K
T is temperature of the vessel = 633 K
V is volume of the vessel = 6.3 L
a & b are Vanderwaal's constant = 6.865 L^2.atm/mol^2 and 0.0567 L/mol respectively.
P = (7.81×0.0821×633)/(6.3 - 7.81×0.05679) - (7.81^2 × 6.865)/6.3^2 = 69.30 - 10.55 = 58.75 atm