Question

A sample of gas occupies a volume of 27 mL at a temperature of 161K. What is the volume of the temperature if raised to 343K?

Answer 1

Answer: The  volume is 57.52 mL if the temperature if raised to 343K.

Explanation:

Given: $V_{1}$ = 27 mL,       $T_{1}$ = 161 K

$V_{2}$ = ?,        $T_{2}$ = 343 K

According to Charles law, at constant pressure the volume of an ideal gas is directly proportional to temperature.

Formula used is as follows.

$\frac{V_{1}}{T_{1}} = \frac{V_{2}}{T_{2}}\\\frac{27 mL}{161 K} = \frac{V_{2}}{343 K}\\V_{2} = 57.52 mL$

Thus, we can conclude that volume is 57.52 mL if the temperature if raised to 343K.