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marshall27 [118]
3 years ago
11

Which best describes the motion of air particles when a transverse wave passes through them?

Physics
1 answer:
Minchanka [31]3 years ago
3 0
C.
The particles move perpendicular to the direction of the wave.
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A robin flies a distance of 45963 cm. How far has it flown in kilometers?
alina1380 [7]

Answer:

0.46km

Explanation:

45963cm/100cm=459.63m/1000m=0.45963 or 0.46km

6 0
3 years ago
A man standing on a bus remains still when the bus is at rest. When the bus moves forward and then slows down the man continues
Stells [14]
C. inertia.  the man is sent flying off the bus because of his weight and the sudden stop of the bus. this effect is called inertia. an example of gravity would be throwing an apple up and having it come to the ground. an example of weight would be putting a man and an elephant on a scale and having the elephant come down while the man goes up.
6 0
3 years ago
How long will it take to travel 200 km traveling 100m/s?
Damm [24]
Convert: 1km = 1000 m 200000 m * 0.01 s/m = 2000 s or 33 minutes and 20 seconds.
7 0
4 years ago
At which temperature does the molecules of an object stop moving?
PilotLPTM [1.2K]

Answer:

at the melting point and boiling point

Explanation:

the heat abdorbed is used to break down the forces holding the particles together to allow it to change its state

7 0
3 years ago
A convex lens has a focal length of 16.5 cm. Where on the lens axis should an object be placed in order to get a virtual, enlarg
alexandr402 [8]

Answer:

Object should be placed at a distance, u = 7.8 cm

Given:

focal length of convex lens, F = 16.5 cm

magnification, m = 1.90

Solution:

Magnification of lens, m = -\frac{v}{u}

where

u = object distance

v = image distance

Now,

1.90 = \frac{v}{u}

v = - 1.90u

To calculate the object distance, u by lens maker formula given by:

\frac{1}{F} = \frac{1}{u}+ \frac{1}{v}

\frac{1}{16.5} = \frac{1}{u}+ \frac{1}{- 1.90u}

\frac{1}{16.5} = \frac{1.90 - 1}{1.90u}

\frac{1}{16.5} = \frac{ 0.90}{1.90u}

u = 7.8 cm

Object should be placed at a distance of 7.8 cm on the axis of the lens to get virtual and enlarged image.

6 0
4 years ago
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