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Umnica [9.8K]
3 years ago
13

At the interface of two transparent media, light ray experiences both refraction and reflection. Does the angle of reflection de

pend on the angle of refraction? Can you demonstrate the effect of total internal reflection using the rectangular block? Explain your answer and support your answer with a drawing. In which case the shift of the light beam passing through the transparent block equals zero?

Physics
1 answer:
juin [17]3 years ago
6 0

Answer:

No, the angle of reflection is independent on the angle of refraction. The total internal reflection is when the angle of incidence is more than the critical angle.

Explanation:

No, the angle of reflection is independent on the angle of refraction. The angle of reflection is only affected by the angle of incidence.

The total internal reflection is when the angle of incidence (I) is more than the critical angle (C). When the light ray pass through the rectangular block, with time, a critical angle will be formed when the refracted ray is exactly 90 degrees to the normal. As soon as the angle of incidence is more than the critical angle, a total internal reflection is formed (as shown in the attached figure).

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Two cars are raised to the same elevation on service- station lifts. If one car is twice as massive as the other, how do their p
Brums [2.3K]

Answer:

The potential energy of the more massive one is twice that of the other.

Explanation:

Potential energy is given by

<em>PE</em> = <em>mgh</em>

where <em>m</em> = mass of body, <em>g</em> = acceleration of gravity and <em>h</em> = height or elevation.

For the less massive car, let the mass be m_1. Then its <em>PE</em> is

PE_1 = m_1gh

For the massive car, let the mass be m_2.  Its <em>PE</em> is

PE_2 = m_2gh

But m_2 =2m_1

\therefore PE_2 = 2m_1gh = 2(m_1gh) = 2PE_1

Hence, the potential energy of the more massive one is twice that of the other.

7 0
3 years ago
A block slides on a table pulled by a string attached to a hanging weight. In case 1 the block slides without friction and in ca
ycow [4]

The tension in the string with friction would be the biggest because of the involvement of the force of gravity. This would result in that the friction force that is acting on the system. There is no friction in the frictionless system, and only the force of gravity is relevant.

7 0
3 years ago
Read 2 more answers
What is an elastic collision?
Anit [1.1K]

Answer:

A collision in which both total momentum and total kinetic energy are conserved

Explanation:

In classical physics, we have two types of collisions:

- Elastic collision: elastic collision is a collision in which both the total momentum of the objects involved and the total kinetic energy of the objects involved are conserved

- Inelastic collision: in an inelastic collision, the total momentum of the objects involved is conserved, while the total kinetic energy is not. In this type of collisions, part of the total kinetic energy is converted into heat or other forms of energy due to the presence of frictional forces. When the objects stick together after the collision, the collisions is called 'perfectly inelastic collision'

6 0
3 years ago
A 2.5-L tank initially is empty, and we want to fill it with 10 g of ammonia. The ammonia comes from a line with saturated vapor
Alex17521 [72]

Answer:

592.92 x 10³ Pa

Explanation:

Mole of ammonia required = 10 g / 17 =0 .588 moles

We shall have to find pressure of .588 moles of ammonia at 30 degree having volume of 2.5 x 10⁻³ m³. We can calculate it as follows .

From the relation

PV = nRT

P x 2.5 x 10⁻³ =  .588 x 8.32 x ( 273 + 30 )

P = 592.92 x 10³ Pa

3 0
3 years ago
Coherent light with wavelength = 600 nm falls on two very narrow closely spaced slits and the interference pattern is observed o
Mrac [35]

Answer:

The distance between the two slits is 1.2mm.    

Explanation:

The physicist Thomas Young establishes, through its double slit experiment, a relationship between the interference (constructive or destructive) of a wave, the separation between the slits, the distance between the two slits to the screen and the wavelength.

\Lambda x = L\frac{\lambda}{d}  (1)

Where \Lambda x is the distance between two adjacent maxima, L is the distance of the screen from the slits, \lambda is the wavelength and d is the separation between the slits.  

If light pass through two slits a diffraction pattern in a screen will be gotten, at which each bright region corresponds to a crest, a dark region to a trough, as consequence of constructive interference and destructive interference in different points of its propagation to the screen.  

Therefore, d can be isolated from equation 1.

d = L\frac{\lambda}{\Lambda x}  (2)

Notice that it is necessary to express L and \lambda in units of millimeters.

L = 4m \cdot \frac{1000mm}{1m} ⇒ 4000mm

\lambda = 600nm \cdot \frac{1mm}{1x10^{6}nm} ⇒ 0.0006mm

d = (4000mm)\frac{0.0006mm}{2mm}

d = 1.2mm

Hence, the distance between the two slits is 1.2mm.

6 0
3 years ago
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