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Umnica [9.8K]
3 years ago
13

At the interface of two transparent media, light ray experiences both refraction and reflection. Does the angle of reflection de

pend on the angle of refraction? Can you demonstrate the effect of total internal reflection using the rectangular block? Explain your answer and support your answer with a drawing. In which case the shift of the light beam passing through the transparent block equals zero?

Physics
1 answer:
juin [17]3 years ago
6 0

Answer:

No, the angle of reflection is independent on the angle of refraction. The total internal reflection is when the angle of incidence is more than the critical angle.

Explanation:

No, the angle of reflection is independent on the angle of refraction. The angle of reflection is only affected by the angle of incidence.

The total internal reflection is when the angle of incidence (I) is more than the critical angle (C). When the light ray pass through the rectangular block, with time, a critical angle will be formed when the refracted ray is exactly 90 degrees to the normal. As soon as the angle of incidence is more than the critical angle, a total internal reflection is formed (as shown in the attached figure).

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6. In baseball, a fastball takes about 1/2 second to reach the plate. Assuming that such a pitch is thrown horizontally, compare
klio [65]

Answer:

<em>The ball falls 0.3 m in the first 1/4 seconds, and it falls 0.92 m in the second 1/4 second</em>

Explanation:

<u>Horizontal Launch </u>

When an object is thrown horizontally with a speed v from a height h, it describes a curved path ruled exclusively by gravity until it eventually hits the ground.

To calculate the vertical distance (y) traveled by the object in terms of the time (t) we use:

\displaystyle y=\frac{g.t^2}{2}

The fastball is thrown horizontally. The distance the ball falls in t=1/4 seconds = 0.25 seconds, is:

\displaystyle y_1=\frac{9.8*0.25^2}{2}

\displaystyle y_1=0.30625\ m

The distance the ball falls in t=1/2 seconds = 0.5 seconds is:

\displaystyle y_2=\frac{9.8*0.5^2}{2}

\displaystyle y_2=1.225\ m

The distance it falls in the second 1/4 second is:

y_2-y_1=1.225\ m-0.30625\ m

y_2-y_1=0.91875\ m

The ball falls 0.3 m in the first 1/4 seconds, and it falls 0.92 m in the second 1/4 second

3 0
3 years ago
What kind of variation is there in the mechanical energy as the cart rolls down the ramp? Does this agree with your prediction?
Harlamova29_29 [7]

Answer:

 Em₀ = U = m g h ,  Em_{f} = K = ½ m v²

Explanation:

When a car is on a ramp it has a certain amount of mechanical energy. At the highest point of the ramp the mechanical energy is fully potential given by

          Em₀ = U = m g h

As part of this energy descends down the ramp, part of this energy is transformed into kinetic energy and has one part of each, even though the sum remains the initial energy

            Em = K + U = ½ m v² + mg y

        y <h

when it reaches the bottom of the ramp it has no height therefore there is no potential energy, all of it has been transformed into kinetic energy

          Em_{f} = K = ½ m v²

This energy transformation is in the case that the friction force is zero.

If there is a friction force, it performs work against the low car, it is reflected in an increase in the internal energy (temperature) of the car. In this case the energy in the lower part is less than the initial one by a factor

         W_{nc} = - fr L

therefore the numeraire values ​​of the velocity are lower, due to the energy lost by friction.

6 0
3 years ago
Which is a compound machine?<br><br> a broom<br> a screwdriver<br> a slide<br> a pair of scissors
8090 [49]
A pair of scissors .....................................
4 0
3 years ago
If the velocity of a pitched ball has a magnitude of 47.0 m/s and the batted ball's velocity is 55.0 m/s in the opposite directi
Naddik [55]

Answer:

14.79 kgm/s

Explanation:

Data provided in the question

Let us assume the mass of baseball =  m = 0.145 kg

The Initial velocity of pitched ball = v_i = 47 m/s

Final velocity of batted ball in the opposite direction = v_f= -55m/s

Based on the above information, the change in momentum is

\Delta P = m(v_f -v_i)

=  0.145 kg(-55m/s - 47m/s)    

= 14.79 kgm/s

Hence, the magnitude of the change in momentum of the ball is 14.79 kg m/s

3 0
3 years ago
Calculate the de Broglie wavelength of an electron traveling at 2.0 x 10^8 m/s (me = 9.1*10^-31 kg).
timofeeve [1]

Answer:

\lambda=3.64\times 10^{-12}\ m

Explanation:

We have,

Speed of an electron is 2\times 10^8\ m/s

It is required to find the De Broglie wavelength of electron. The formula for the De- Broglie wavelength is given by :

\lambda=\dfrac{h}{mv}

h is Planck's constant

m is mass of an electron

Plugging all the values we get :

\lambda=\dfrac{6.63\times 10^{-34}}{9.1\times 10^{-31}\times 2\times 10^{8}}\\\\\lambda=3.64\times 10^{-12}\ m

So, the De-Broglie wavelength of an electron is 3.64\times 10^{-12}\ m

4 0
3 years ago
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