Answer:
The percentage of the weight supported by the front wheel is A= 19.82 %
Explanation:
From the question we are told that
The center of gravity of the plane to its nose is 
The distance of the front wheel of the plane to its nose is 
The distance of the main wheel of the plane to its nose is 
At equilibrium the Torque about the nose of the airplane is mathematically represented as
Where m is the mass of the airplane
is the weight of the airplane supported by the main wheel
So
Substituting values
Now the weight supported at the frontal wheel is mathematically evaluated as
Substituting values
Now the weight of the airplane is = mg
Thus percentage of this weight supported by the front wheel is 
19.82 %
From the average speed you can fix an equation:
Average speed = distance / time
You know the average speed = 65.1 kg / h, then
65.1 = distance / total time,
where total time is the time traveling plus 22.0 minutes
Call t the time treavelling and pass 22 minutes to hours:
65.1 = distance / [t + 22/60] ==> distance = [t + 22/60]*65.1
From the constant speed, you can fix a second equation
Constant speed = distance / time traveling
94.5 = distance / t ==> distance = 94.5 * t
The distance is the same in both equations, then you have:
[t +22/60] * 65.1 = 94.5 t
Now you can solve for t.
65.1t + 22*65.1/60 = 94.5t
94.5t - 65.1t = 22*65.1/60
29.4t = 23.87
t = 23.87 / 29.4
t = 0.812 hours
distance = 94.5 km/h * 0.812 h = 76.7 km
Answers: 1) 0.81 hours, 2) 76.7 km
The 4 significant figures of 31,546,000 are all 8 of the digits.
Scalar quantities have only a magnitude. So the answer is scalar quantities.
