I think its the car moving to a stop sign
D = vo t - at²/2
v = vo - at
40 m = vo · 7.10 - a · ( 7.10 )²/2
40 m = 7.10 vo - a· 50.41/2
40 m = 7.10 vo - 25.205 a
2.75 m/s = vo - 7.10 a ⇒ a = ( vo - 2.75 )/ 7.10
40 = 7.10 vo - 25.205 · ( vo - 2.75 ) / 7.10
40 = 7.1 vo - 3.55 vo + 9.7625
3.55 vo = 30.2375
vo = 30.2375 : 3.55 = 8.5176 m/s
Answer: the truck`s original speed is 8.5176 m/s.
Answer:
|X| = 72 cm
Explanation:
We need to find the magnitude of vector X.
Vector Y = 21 cm
Vector Z = 75 cm
We know that, the magnitude of resultant vector is given by :
So, the value of magnitude of vector X is 72 cm
Answer:
<span>5010J</span>
Explanation:
Work is force times distance, or
<span>W=F⋅d</span>.
Substitute in values from the question to get
<span>W=8.35⋅<span>102</span>N⋅6m=50.1⋅<span>102</span>Nm=5010<span>J</span></span>
