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valentinak56 [21]
2 years ago
12

Moving along the elevtromagnetic spectrum from low frequency to high frequency, what , if anything, happens to the wavelength?

Physics
1 answer:
jenyasd209 [6]2 years ago
3 0

Explanation:

the wavelengths get shorter

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Two sound waves are traveling through the same medium. They have the same amplitude, wavelength, and direction of travel. If the
Sloan [31]

Answer:

Constructive interference

Explanation:

Here, the medium is same, same wavelength, same frequency, same amplitude and same direction of propagation.

Let the intensity of waves be I which is same for both

The formula for the net intensity is

I^{2}=I_{1}^{2}+I_{2}^{2}+2I_{1}I_{2}Cos\phi

where, Ф be the phase difference

So, I_{R}^{2}=I^{2}+I^{2}+2IICos6\pi

Here, IR is maximum so the interference is constructive in nature.

7 0
3 years ago
How is newton's first law used in basketball?
arlik [135]

Newton's first law of motion states that an object at rest tends to stay at rest, while an object in motion tends to stay in motion unless an external force acts upon it. This law appears in basketball when the player is shooting the ball. When the player is holding the ball, the ball is at rest but when a player shoots the ball, they use force to throw the ball in the hoop.

4 0
3 years ago
PLS HELP!! YOU CAN SKIP THE INFO IF YOU WANT!!
agasfer [191]

Answer:

B

Explanation:

The whole thing is talking about the damage runoffs have done that is equal to answer B.

5 0
2 years ago
Read 2 more answers
How far should the second antenna be moved in order to receive a minimum signal from a station that broadcasts at 99.4 MHz?
raketka [301]

Answer:

So the distance of the antenna from the station will be 3.018 m

Explanation:

We have given the frequency of the broadcast f=99.4MHz=99.4\times 10^4Hz

The speed of light c=3\times 10^8m/sec

The distance of the antenna to receive a minimum signal from the station is given by d=\frac{v}{f}=\frac{3\times 10^{8}}{99.4\times 10^6}=3.018m

So the distance of the antenna from the station will be 3.018 m

5 0
3 years ago
In the demolition of an old building, a 1,300 kg wrecking ball hits the building at 1.07 m/s2. Calculate the amount of force at
Y_Kistochka [10]

Answer: F = 1391 N

Explanation:

The information given to you are:

Mass M = 1300 kg

Acceleration a = 1.07 m/s^2

The magnitude of the force striking the building will be

F = ma

Where

F = force

Substitute mass M and acceleration a into the formula

F = 1300 × 1.07

F = 1391 N

Therefore, the wrecking ball strikes the building with a force of 1391 N

3 0
3 years ago
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