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ki77a [65]
3 years ago
15

PLEASE HELP ASAP PHYSICS QUESTION!!

Physics
2 answers:
ohaa [14]3 years ago
7 0

Assuming this is a continuation of an earlier question [20398149], the crate starts at rest and is allowed to slide down the ramp with acceleration <em>a</em> = 2.35 m/s², so the block will have some speed as it reaches the bottom of the ramp and it will continue to slide some distance along the flat part.

If the flat part is made of the same material as the ramp, then in addition to its own weight and the normal force, the crate will also feel some friction that slows down its leftward slide.

• The crate's weight and the normal force act vertically, so that

∑ <em>F</em> = <em>n</em> - <em>w</em> = 0

<em>n</em> = <em>w</em> = <em>mg</em> = (100 kg) (9.8 m/s²) = 980 N

(where ∑ <em>F</em> = net force, <em>n</em> = magnitude of normal force, <em>w</em> = crate weight, <em>m</em> = crate mass, <em>g</em> = mag. of gravitational acceleration)

• The friction acts horizontally, so

∑ <em>F</em> = -<em>f</em> = <em>m a</em>

(where <em>f</em> = mag. of friction and <em>a</em> = crate acceleration)

The surface has a coefficient of kinetic friction of <em>µ</em> = 0.3, so

<em>f</em> = <em>µ</em> <em>n</em> = 0.3 (980 N) = 294 N

So at the bottom of the ramp, there are 3 forces exerted on the crate:

• its weight of 980 N pointing downward

• the normal force of the surface pushing upward on the crate, also of 980 N

• friction of 294 N, pointing to the right

and the two vertical forces cancel each other.

ivann1987 [24]3 years ago
6 0

Answer:

There will be a force of gravity and a normal force coming from the track itself.

Explanation:

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Now,

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Now, using eqn (1), we get:

\frac{v_{b}}{v_{a}} = \frac{\rho_{a}}{\rho_{b}}

\frac{v_{b}}{v_{a}} = \frac{1.20}{1.05} = 1.14

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There's an electric field in some region of space that doesn't change with position. An electron starts moving with a speed of 2
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Answer:

Explanation:

Given

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final speed of Electron v=4\times 10^7\ m/s

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using equation of motion

v^2-u^2=2as

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a=acceleration

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(4\times 10^7)^2-(2\times 10^7)^2=2\times a\times 1.2\times 10^{-2}

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3 years ago
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QveST [7]

Answer:

(c) position

Explanation:

From the work-energy theorem, the workdone by a force on a body causes a change in kinetic energy of the body.

But, remember that the work done (W) by a force (F) on a body is the product of the force and the distance d, moved by the body caused by the force. i.e

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Answer:

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(C) is correct option.

Explanation:

Given that,

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For second half,

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t_{2}=\sqrt{\dfrac{2h}{g}}

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