Hi! In 3 seconds the object will fall approximately 44 meters.
KE = 1/ 2 * 1252 * 144
as KE = 1/2 * m * v ^2
= 90144 J
The correct match of each item to the clean water regulation it describes is as follows:
- Regulates pollutants discharged into surface waters: Clean water act
- Covers both surface and ground waters: Safe drinking water act
- Authorizes the EPA to establish minimum standards for tap water: Safe drinking water act
- Funds sewage treatment plants: Clean water act
<h3>What are the functions of clean water regulation?</h3>
Clean Water Act (CWA) is a regulatory body that establishes the basic structure for the regulation of pollutants discharge and maintenance of quality standards of the surface waters.
On the other hand, the Safe Drinking Water Act was founded to oversee the protection of the quality drinking water. The regulatory body is primarily concerned with potable water all waters, whether from above ground or underground sources.
Therefore, the correct match of each item to the clean water regulation it describes is as follows:
- Regulates pollutants discharged into surface waters: Clean water act
- Covers both surface and ground waters: Safe drinking water act
- Authorizes the EPA to establish minimum standards for tap water: Safe drinking water act
- Funds sewage treatment plants: Clean water act
Learn more about clean water regulation at: brainly.com/question/2142268
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Answer:
The average recoil force on the gun during that 0.40 s burst is 45 N.
Explanation:
Mass of each bullet, m = 7.5 g = 0.0075 kg
Speed of the bullet, v = 300 m/s
Time, t = 0.4 s
The change in momentum of an object is equal to impulse delivered. So,
For 8 shot burst, average recoil force on the gun is :
So, the average recoil force on the gun during that 0.40 s burst is 45 N.
Answer:
To find out the area of the hot filament of a light bulb, you would need to know the temperature, the power input, the Stefan-Boltzmann constant and <u>Emissivity of the Filament</u>.
Explanation:
The emissive power of a light bulb can be given by the following formula:
E = σεAT⁴
where,
E = Power Input or Emissive Power
σ = Stefan-Boltzmann constant
ε = Emissivity
A = Area
T = Absolute Temperature
Therefore,
A = E/σεT⁴
So, to find out the area of the hot filament of a light bulb, you would need to know the temperature, the power input, the Stefan-Boltzmann constant and <u>Emissivity of the Filament</u>.
