The velocity of the ball when it was caught is 12.52 m/s.
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find the velocity of the ball when it was caught.
The given parameters;
maximum height above the ground reached by the ball, H = 38 m
height above the ground where the ball was caught, h = 30 m
The height traveled by the ball when it was caught is calculated as follows;
y = H - h
y = 38 - 30 = 8 m
The velocity of the ball when it was caught is calculated as;
Thus, the velocity of the ball when it was caught is 12.52 m/s.
Learn more here: brainly.com/question/14582703
Any unit of acceleration must have the dimensions (form) of
(a unit of length) / (a unit of time)²
Answer:
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Explanation:
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Unless if all forces cancel each other out , the object will no longer be in equilibrium