Answer:
The velocity is 
Explanation:
From the question we are told that
The first distance is 
The first speed is 
The second distance is 
The second speed is 
Generally the time taken for first distance is
The time taken for second distance is
The total time is mathematically represented as
=> 
=> 
Generally the constant velocity that would let her finish at the same time is mathematically represented as
=> 
=>
Draw a free body diagram to show which forces act in the x and y directions. The x component equation is σfx = 0. The σfx being all the forces acting in the x direction.
Answer:
The acceleration of a 1000 kg car subject to a 550 N net force = 0.55 m/s^2
Explanation:
Given:
F = 550 N
m = 1000 kg
To Find:
a = ?
Solution:
So by the equation by Newton's 2nd Law of Motion,
F = m x a
550 N = 1000 kg x a
a = 550 N/ 1000 kg
a = 0.55 m/s^2
Therefore,
The acceleration of a 1000 kg car subject to a 550 N net force = 0.55 m/s^2
PLEASE MARK ME AS BRAINLIEST!!!
I would assume air resistance is negligible and so the acceleration of the package would be approximately 9.81 m/s².
Taking downwards as positive, use v²=u²+2as.
v²=(-2)²+2(9.81)(14)
v=16.7 m/s
Answer:
Explanation:
v = u +at
u = 0
a = 2.3 m /s²
t = 20 s
v = 2.3 x 20
= 46 m /s
Distance covered under acceleration of 2.3 m/s²
s = ut + 1/2 at²
= 0 + .5 x 2.3 x 20²
= 460 m
After that it moves under free fall ie g acts on it downwards .
v² = u² - 2gh , h is height moved by it under free fall
0 = 46² - 2 x 9.8 h
h = 107.96 m
Total height attained
= 460 + 107.96
= 567.96 m
b ) At its highest point ,it stops so its velocity = 0
c ) rocket's acceleration at its highest point = g = 9.8 downwards .
At highest point , it is undergoing free fall so its acceleration = g
