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tekilochka [14]
3 years ago
8

What is a solute?

Physics
2 answers:
Vinvika [58]3 years ago
8 0
Answer :

- The that gets dissolved
kolbaska11 [484]3 years ago
7 0

Answer:

C.) The substance that gets dissolved

Explanation:

Because i am a wise man

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What is the power involved in lifting a 10-kg object 1.0 m in 0.50 s?
Sedbober [7]
In this question, we know that mass= 10 kg = 10 x 1000 = 10,000 g
Distance = 1 m and Time = 0.5 s

Power = Force x Velocity
Velocity = Distance / Time = 1 m / 0.5 s = 2 m/s
So, Power  = Force x (Distance / Time)
But Force= Mass x Acceleration due to gravity (g)
So, Force = 10 kg  x 9.8 m/s^{2} = 98
Therefore, Power =Force x Velocity= 98 x 2 = 196 W
5 0
3 years ago
Light of wavelength 510 nm is used to illuminate normally two glass plates 24.3 cm in length that touch at one end and are separ
bulgar [2K]

Answer:

m = 180 \ bright \ fringes

Explanation:

From the question we are told that

    The  wavelength is  \lambda  =  510 \ nm = 510 *10^{-9} \  m

    The length of the of the plate is  l  =  24.3 \ cm  =  0.243 \  m

    The radius of the wire  is r=  0.023 \ mm  =  2.3 *10^{-5} \ m

Generally the diameter of the wire which is the distance between the glass  plates is mathematically represented as

             d =  2 *   r

=>          d =  2 *   2.3 *10^{-5}

=>          d =  4.6 *10^{-5} \  m

 Generally the condition for constructive interference is mathematically represented as

           2 *d = m \lambda

=>        m = \frac{2d}{\lambda}

=>        m = \frac{2 * (4.6* 10^{-5})}{ 510 *10^{-9} }

=>        m = 180 \ bright \ fringes

3 0
3 years ago
Which of these is a key feature of an experimental study?
Pavlova-9 [17]
The key feature in the experimental study is C. <span>The treatment in the experiment must be applied to each of the individuals in the experimental group. This is because it is made sure that the variables and conditions in different correspondents are applied so that actual results may be concluded.</span>
7 0
3 years ago
Read 2 more answers
Sawyer launches his 180 kg raft on the Mississippi River by pushing on it with a force of 75N. How long must Sawyer push on the
Daniel [21]

Answer: 4.8 s

Explanation:

We have the following data:

m=180 kg the mass of the raft

F=75 N the force applied by Sawyer

V=2 m/s the raft's final speed

V_{o}=0 m/s the raft's initial speed (assuming it starts from rest)

We have to find the time t

Well, according to Newton's second law of motion we have:

F=m.a (1)

Where a is the acceleration, which can be expressed as:

a=\frac{\Delta V}{\Delta t}=\frac{V-V_{o}}{t-t_{o}} (2)

Substituting (2) in (1):

F=m\frac{V-V_{o}}{t-t_{o}} (3)

Where t_{o}=0

Isolating t from (3):

t=\frac{m(V-V_{o})}{F} (4)

t=\frac{180 kg(2 m/s-0 m/s)}{75 N}

Finally:

t=4.8 s

6 0
3 years ago
If a car has a mass of 200 kilograms and produces a force of 500 N, how fast will the car accelerate?
san4es73 [151]

Answer:

B

Explanation:

F = ma

500N = 200 × a

200a. = 500N

a. =. 500N/200

a. =. 2.5m/s²

PLEASE GIVE BRAINLIEST.

3 0
3 years ago
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