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Rudiy27
3 years ago
13

a farmer moves along the boundary of a square field of side 10 m in 40 s.what will be the magnitude of displacement of the farme

r at the end of 2 minutes 20 seconds from his initial position ?
Physics
1 answer:
melamori03 [73]3 years ago
7 0

Answer:

i think 80 m.

Explanation:

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How are land-use laws in the United States different from the land-use laws inherited from England?
exis [7]

private property owners in the United States can restrict public access to their land

5 0
3 years ago
The main benefit you receive from using locomotor movements in a variety of activities is?
adell [148]

Answer:The locomotor skills include: walking, running, skipping, galloping, hopping, jumping, sliding, walking backwards, and leaping. Students are learning these skills at it could take lots of practice to develop the skills necessary to complete all of the locomotor skills.

Explanation:

7 0
3 years ago
Create a file "parts_inv.dat" that stores on each line a part number, cost, and quantity in inventory, in the following format:1
andriy [413]

Answer:

%Open the file.

fID = fopen('parts_inv.dat');

%Read from the file.

data = fscanf(fID,'%d\t%f\t%d',[3,inf]);

%Close

fclose(fID);

%Restore the data.

data = data';

%Get the size

[rs, cs] = size(data);

%Set value.

invCost = 0;

%Loop

for rw = 1 : rs

%Find cost

invCost = invCost + (data(rw, 2) * data(rw, 3));

%Loop end

end

%Display the cost.

fprintf('Total cost: %4.2f\n\n', invCost);

Explanation:

7 0
4 years ago
a missile is moving 1810 m/s at a 20.0. It needs to hit a target 29,500m away in a 65.0 magnitude in 9.20s. What acceleration mu
Vesna [10]

Answer:

323 m/s²

Explanation:

Given:

x₀ = 0 m

y₀ = 0 m

x = 29500 cos 65°

y = 29500 sin 65°

v₀x = 1810 cos 20°

v₀y = 1810 sin 20°

t = 9.20

Find:

ax, ay, θ

First, in the x direction:

x = x₀ + v₀ t + ½ at²

29500 cos 32° = 0 + (1810 cos 20°) (9.20) + ½ ax (9.20)²

25017 = 15648 + 42.32 ax

ax ≈ 221.4

And in the y direction:

y = y₀ + v₀ t + ½ at²

29500 sin 32° = 0 + (1810 sin 20°) (9.20) + ½ ay (9.20)²

15633 = 5695 + 42.32 ay

ay ≈ 234.8

Therefore, the magnitude of the acceleration is:

a² = ax² + ay²

a² = (221.4)² + (234.8)²

a ≈ 322.7

Rounded to 3 significant figures, the magnitude of the acceleration is approximately 323 m/s².

7 0
3 years ago
How does speed affect momentum
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Momentum = mass • velocity
M = m • v

Speed is a scalar quantity
Velocity is a vector quantity

That is truly the only difference
8 0
3 years ago
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