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3 years ago

The force exerted by the earth on a body is called ______of a body.

Physics

2 answers:

Leno4ka [110]3 years ago

7 0

Answer:weight

Explanation:

AVprozaik [17]3 years ago

4 0

Answer:

The force exerted by the earth on a body is called gravitational of a body.

i think this is the answer

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An electric field of 8.20 ✕ 105 V/m is desired between two parallel plates, each of area 25.0 cm2 and separated by 2.45 mm. Ther

astraxan [27]

Answer:

q = 1.815 \times 10^{-8} C

Charge on one plate is positive in nature and on the other plate it is negative in nature.

Explanation:

E = 8.20 x 10^5 V/m, A = 25 cm^2, d = 22.45 mm

According to the Gauss's theorem in electrostatics

The electric field between the two plates

$E = \frac{\sigma }{\varepsilon _{0}}$

${\sigma }= E \times {\varepsilon _{0}}$

${\sigma }= 8.20 \times 10^{5} \times {8.854 \times 10^{-12}$

${\sigma }= 7.26 \times 10^{-6} C/m^{2}$

Charge, q = surface charge density x area

$q = 7.26 \times 10^{-6} \times 25 \times 10^{-4}$

q = 1.815 \times 10^{-8} C

5 0

3 years ago

Heating up a reaction speeds up the rate of the reaction because...

kherson [118]

Answer:

Explanation:

more heat = heat energy becomes more kinetic energy = more particle collision

3 0

3 years ago

Read 2 more answers

When hiking at altitude, the air pressure drops to 825,000Pa. Solve the force that site exerts against the side of a rectangular

OLga [1]

Answer:

The force is $1237500N$

Explanation:

We can apply the following expression

$pressure=\frac{Force}{Area}$

To find the area of rectangular tent wall:

$Area=length *width\\Area=2.00m*0.750m\\Area=1.5m^{2}$

Now to find the force:

$pressure=825,000pa$

$pressure=\frac{Force}{Area}$

$Force=pressure*Area\\Force=825000pa*1.5m^{2} \\Force=1237500N$

7 0

3 years ago

How far must you be from a 110 W speaker to have an intensity of 0.0439 W/m^2? (Treat the speaker as a point source.)

Lina20 [59]

Answer:

$d=14.12m$

Explanation:

Assume a point sound source that emits a sound power P (in W) evenly in all directions of space. Let us also assume that the medium does not absorb this sound power when it passes through it. At a distance d from the source this power will have been evenly distributed over the surface of a sphere of radius d. Therefore, the acoustic intensity I at distance d will be worth:

$I=\frac{P}{4\pi d^{2}}$

This is the expression of the so-called law of the square of distance: "the intensity is inversely proportional to the square of the distance to the source (considered punctual)".

$I=0.0439 \frac{W}{ m^{2}}$