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2 years ago

The force exerted by the earth on a body is called ______of a body.

Physics

2 answers:

Leno4ka [110]2 years ago

7 0

Answer:weight

Explanation:

AVprozaik [17]2 years ago

4 0

Answer:

The force exerted by the earth on a body is called gravitational of a body.

i think this is the answer

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A car initially traveling at 27.7 m/s undergoes a constant negative acceleration of magnitude 2.00 m/s2 after its brakes are app

lys-0071 [83]

The car's velocity at time t is given by

$v=27.7\dfrac{\rm m}{\rm s}+\left(-2.00\dfrac{\rm m}{\mathrm s^2}\right)t$

It comes to a stop when v = 0, which happens when

$0=27.7\dfrac{\rm m}{\rm s}+\left(-2.00\dfrac{\rm m}{\mathrm s^2}\right)t\implies t=13.85\,\mathrm s$

or after about 13.9 s.

In this time, the car travels a distance x given by

$x=\left(27.7\dfrac{\rm m}{\mathrm s}\right)(13.85\,\mathrm s)+\dfrac12\left(-2.00\dfrac{\rm m}{\mathrm s^2}\right)(13.85\,\mathrm s)^2=191.823\,\mathrm m$

or about 192 m.

In one complete revolution, each tire covers a distance equal to its circumference,

$2\pi(0.340\,\mathrm m)\approx2.13628\,\mathrm m$

or about 2.14 m.

This means each tire will complete approximately 192/2.14 ≈ 90 revolutions.

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2 years ago

If substance a and substance b have very different values for the index of refraction, what will happen to a light ray that pass

dmitriy555 [2]

I think it will be deflected by a great amount
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5 0

2 years ago

A 75N force is applied to a 15kg box. If the box

icang [17]

Answer:

The coefficient of kinetic friction is 0.51.

Explanation:

Given that,

Applied force, F = 75 N

Mass of a box, m = 15 kg

The acceleration of the box is 3 m/s²

We need to find the coefficient of kinetic friction. It is given by the formula as follows :

$F=\mu_k F_N$

Where,

$F_N=mg$ , is the normal force

$\mu_k=\dfrac{F}{mg}\\\\\mu_k=\dfrac{75}{15\times 9.8}\\\\\mu_k=0.51$

So, the coefficient of kinetic friction is 0.51.

6 0

2 years ago

A train moves at constant velocity of 90km/h. How far will it go in 0.25h.

enot [183]

In a quarter of an hour it will travel 1/4 x 90 = 22.5Km

8 0

2 years ago

In a hydroelectric power plant, 65 m3 /s of water flows from an elevation of 90-m to a turbine-generator, where electricity is g

Mariulka [41]

The electric output of the plant is 48.19 MW

First we need to calculate the water power, it is given by the formula

WP=ρQgh

Here, ρ=1000 kg/m3 is density of water,Q is the flow rate, g is the gravity, and h is the water head

Therefore, WP=1000*65*9.81*90=57388500 W=57.38 MW

Now the overall efficiency of the hydroelectric power plant is given as

η= $\frac{electric power}{water power}$

Plugging the values in the above equation

0.84=EP/57.38

EP=48.19 MW

Therefore, the electric output of the plant is 48.19 MW.

3 0

2 years ago