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Kryger [21]
3 years ago
11

Two objects of the same mass travel in opposite directions along a horizontal surface. Object X has a speed of 5ms and object Y

has a speed of 5ms, as shown in the figure. After a period of time, object X collides with object Y. In scenario 1, the objects stick together after the collision. In scenario 2, the objects do not stick together after the collision.
Which of the following claims is true regarding how the outcome of scenario 1 is different from the outcome of scenario 2?
Physics
2 answers:
Papessa [141]3 years ago
8 0

Answer:

1

Explanation:

Because theyre heading opposite directions

alexdok [17]3 years ago
8 0
Since both objects are travelling in opposite directions at the same speed but eventually colliding with each other hence it is obvious that they are travelling in a circle.

Now, this question is regarding the conversation of momentum - elastic / in elastic collision.

Assuming the balls are in a closed system(an assumption that is consistent in your syllabus,unless stated otherwise)as the ball collides, momentum is conserved but some of the energy might be lost due to the collision either through heat / sound.

Summary:

3 types of collision.

1st type: Elastic collision
- No loss in Kinetic Energy
- No loss in momentum
- Balls do not stick together
Example: Bouncing Basketball, the ball comes back to your hand at the same height.

2nd type: Inelastic collision
- Loss in kinetic energy, (heat energy when in contact)
- No loss in momentum
- Balls do not stick together
Example: Bomb explosion.

3rd type: Perfectly Inelastic collision
- Maximum amount of KE is loss
- No loss in momentum
- Balls stick together
Example: Ballistic Pendulum
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A student drove to the university from her home and noted that the odometer on her car increased by 16.0 km. The trip took 19.0
777dan777 [17]

ANSWER:

a. 50.53 km/h

b. 32.53 km/h (in the direction of 25˚ S of E)

c. 4.27 km/h

d. 0 km/h

STEP-BY-STEP EXPLANATION:

a.

We have that the speed is given by the following formula:

\begin{gathered} s=\frac{d}{t} \\ \text{ where s is the speed, d is the distance and t is the time} \end{gathered}

We know that the equivalence between minutes and hours is that 60 minutes equals 1 hour, therefore:

s=\frac{16\text{ km}}{19\text{ }\min\frac{1\text{ h}}{60\text{ min}}}=50.53\text{ km/h}

b.

The velocity is given by the following formula

\begin{gathered} v=\frac{\Delta x}{t} \\ \text{replacing:} \\ v=\frac{10.3\text{ km-}0\text{ km}}{19\text{ }\min \frac{1\text{ h}}{60\text{ min}}}=32.53 \end{gathered}

c.

The total distance traveled would then be two 16 kilometers, that is 32 km and the time would be 7.5 hours. we replace

s=\frac{32\text{ km}}{7.5\text{ h}}=4.27\text{ km/h}

d.

Since it starts in the same place that it ends, the displacement is equal to 0, therefore, the velocity is equal to 0 km/h

5 0
2 years ago
During their physics field trip to the amusement park, Tyler and Maria took a rider on the Whirligig. The Whirligig ride consist
blondinia [14]

Answer:

Speed = 7.04434 m/s

Explanation:

Given that:

The radius of the circle = 6.5 m

The expression for the calculation of circumference is shown below as:

Circumference=2\times \pi \times radius

Thus,

Circumference=2\times \frac{22}{7} \times 6.5\ m=40.8572\ m

Time taken = 5.8 seconds.

Thus, The speed is:

Speed=\frac{Circumference}{Time\ Taken}

So,

Speed=\frac{40.8572}{5.8}\ m/s

<u>Speed = 7.04434 m/s</u>

8 0
4 years ago
Read 2 more answers
Two cars start a race with initial velocity 7ms-1 and 4ms-1 respectively.Their acceleration are 0.4ms-2 and 0.5ms-2 respectively
Ronch [10]

The distance of the track is 600 m

Explanation:

The two cars move by uniformly accelerated motion, so we the distance they cover after a time t is described by the following suvat equation

d=ut+\frac{1}{2}at^2

where

u is the initial velocity

a is the acceleration

For car 1, we have

d_1 = u_1 t + \frac{1}{2}a_1 t^2

where

u_1 = 7 m/s is the initial velocity of car 1

a_1 = 0.4 m/s^2 is the acceleration of car 1

So the equation can be rewritten as

d_1 = 7t + 0.2t^2

For car 2, we have

d_2 = u_2 t + \frac{1}{2}a_2 t^2

where

u_2 = 4 m/s is the initial velocity of car 2

a_2 = 0.5 m/s^2 is the acceleration of car 2

So the equation can be rewritten as

d_2= 5t + 0.25t^2

The two cars finish the race at the same time: this means that they cover the same distance in the same time t, so we can write

d_1 = d_2\\7t + 0.2t^2=5t + 0.25t^2

And solving for t, we find

2t - 0.05t^2= 0\\t(2-0.05t)=0

Which gives two solutions:

t = 0 (initial instant)

t = 40 s

Therefore, the distance of the track is

d_1 = 7t +0.2t^2 = 7\cdot 40+0.2\cdot 40^2=600 m

Learn more about accelerated motion:

brainly.com/question/9527152

brainly.com/question/11181826

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brainly.com/question/2562700

#LearnwithBrainly

7 0
4 years ago
Wan and Nurul sat on a see-saw. The see-saw is imbalanced because Wan’s mass is 45 kg while Nurul’s mass is only 30 kg. Suggest
Alex Ar [27]

We have that the see-saw will be balance if a weight of x=15kg is added to Nural's side of the see-saw

x=15kg

From the Question we are told that

Wan’s mass is M_w=45 kg

Nurul’s mass is M_n= 30 kg.

Generally

The Will be balance when the weight on both sides of the see-saw are equal

M_w=M_n+x

45=30+x

x=45-30

x=15kg

In conclusion

The see-saw will be balance if a weight of x=15kg is added to Nural's side of the see-saw

x=15kg

For more information on this visit

brainly.com/question/22255610

5 0
3 years ago
surface is tipped to all principal planes of projection. Because it is not perpendicular to any projection plane, it cannot appe
Aleksandr [31]

Answer:

Oblique surface

Explanation:

Surfaces or lines situated at an angle in relation to all the main projection planes are oblique. An oblique surface never appears in any of the main perspectives as a line or true size area. It's Tipped to all main projection planes. doesn't quite appear on the edge of every standard view. doesn't quite show up in any view in true size.it has always been foreshortened.

7 0
3 years ago
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