Answer:
When she stretches her arms out,<em> B) her angular speed ω increases due to her moment of inertia decreasing</em>
Explanation:
The angular momentum of a rotating object is defined as the product of its moment of inertia and angular speed.
<em>L = I ω</em>
<em>where</em>
- <em>L is the angular momentum</em>
- <em>I is the moment of inertia</em>
- <em>ω is the angular speed</em>
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According to the principle of conservation of angular momentum, if there is no external torque, angular momentum of the skater must remain conserved. If the initial and final moment of inertia is <em>I_i and I_f </em>while corresponding angular velocities are <em>ω_i and ω_f , </em>then the principle of conservation of angular momentum can be expressed as the following equation:
<em>(I_f) (ω_f) = (I_i) (ω_i)</em>
<em>ω_f / ω_i = I_i / I_f</em>
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From the expression above, we can see that if the moment of inertia decreases, angular velocity would increase to conserve angular momentum of the skater.
Therefore, When she stretches her arms out,<em> her angular speed ω increases due to her moment of inertia decreasing.</em>
Interesting I guess not much you put
You've described two (2) axes of motion.
The third one would have been up-and-down.
<u>Answer:</u> The mass of the second car is 12666.7 kg
<u>Explanation:</u>
To calculate the mass of car, we use the equation of law of conservation of momentum, which is:
where,
= mass of car 1 = 9500 kg
= Initial velocity of car 1 = 14 m/s
= mass of car 2 = ? kg
= Initial velocity of car 2 = 0 m/s
= Final velocity = 6.0 m/s
Putting values in above equation, we get:
Hence, the mass of the second car is 12666.7 kg
Charge dQ on a shell thickness dr is given by
dQ = (charge density) × (surface area) × dr
dQ = ρ(r)4πr²dr
∫ dQ = ∫ (a/r)4πr²dr
∫ dQ = 4πa ∫ rdr
Q(r) = 2πar² - 2πa0²
Q = 2πar² (= total charge bound by a spherical surface of radius r)
Gauss's Law states:
(Flux out of surface) = (charge bound by surface)/ε۪
(Surface area of sphere) × E = Q/ε۪
4πr²E = 2πar²/ε۪
<span>E = a/2ε۪
I hope my answer has come to your help. Thank you for posting your question here in Brainly. We hope to answer more of your questions and inquiries soon. Have a nice day ahead!
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