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Black_prince [1.1K]
3 years ago
9

An object weighs 39.36 newtons. What is its mass if a gravitometer indicates that g = 9.83 m/s2?

Physics
2 answers:
CaHeK987 [17]3 years ago
6 0
The force applied to an object is said to be a product of its mass and the acceleration. For this case, acceleration is the reading on the gravitometer. We calculate as follows:

F = mg
39.36 N = m(9.83 m/s^2)
m = 4.00 kg

Hope this answers the question. Have a nice day.
IrinaVladis [17]3 years ago
6 0

Answer:

4.0 kilograms.

Explanation:

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3 years ago
0.10-kilogram model rocket’s engine is designed to deliver an impulse of 6.0 newton-seconds. If the rocket engine burns for 0.75
UkoKoshka [18]

Answer:

8.0 N

Explanation:

Force: This can be defined as the mass of a body and its acceleration. The S.I unit of Force is Newton (N).

Mathematically, Fore is expressed as

F = ma ........................... equation 1

Where F = force, m = mass, a = acceleration.

and

I = mΔv

Δv = I/m ............................ Equation 2

Where I = impulse, m = mass, Δv = change in velocity

Given: I = 6.0 Newton-seconds, m = 0.1 kilogram.

Substituting into equation 2

Δv = 6.0/0.1

Δv = 60 m/s.

But

a = Δv/t

where t = time = 0.75 seconds.

a = 60/0.75

a = 80 m/s²

Substitute the values of a and m into equation 1.

F = 0.1(80)

F = 8.0 N.

Thus the average force produced = 8.0 N

6 0
3 years ago
Two light bulbs are installed in two sockets, the sockets are connected in series, and power is then applied to the combination
Arisa [49]

Answer:

False

Explanation:

<em>If one of the bulbs is removed from the series, the other bulb will not come on at all.</em>

This is because the removal of one of the bulbs would interrupt the flow of current though the entire circuit.

Hence, that the other one will get brighter if one of two bulbs in a circuit is removed from its socket is not true.

5 0
3 years ago
According to Boyle’s Law, increasing the pressure of a gas will have which effect on its volume? increase decrease random effect
umka21 [38]
Volume will decrease if the heat remains constant
3 0
3 years ago
What is the frequency of a monochromatic light used in a diffraction experiment that has a wavelength of 6.38 ✕ 10e-07 m?
Lady_Fox [76]

Answer:

f=4.70\times 10^{14}\ Hz

Explanation:

Given that,

The wavelength of light, \lambda=6.38\times 10^{-7}\ m

We need to find the frequency of the light. We know that,

c=f\lambda\\\\f=\dfrac{c}{\lambda}\\\\f=\dfrac{3\times 10^8}{6.38\times 10^{-7}}\\\\f=4.70\times 10^{14}\ Hz

So, the required frequency of light is equal to 4.70\times 10^{14}\ Hz.

4 0
3 years ago
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