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Troyanec [42]
2 years ago
10

Give 3 combinational logic circuits on basic electronic devices that can be found at home.

Physics
2 answers:
Novay_Z [31]2 years ago
5 0

Answer: ptop tv calculator

Explanation:

Umnica [9.8K]2 years ago
4 0

Answer:

Leds switchs battery

Explanation:

....................

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Find the frequency, if the amplitude of a 3000g object in simple harmonic motion is 1000cm and the maximum speed of the object i
Oksana_A [137]

Answer:

A = 10 m     amplitude

m = 3 kg     mass of object

Vm = 5 m/s

w A = Vm      where w = omega

w = 2 * pi * f

2 * pi * f  10 = 5

f = 5 / (20 * pi)  = .0796 / sec

7 0
2 years ago
Given that the wavelengths of visible light range from 400 nm to 700 nm, what is the highest frequency of visible light? (ccc =
enot [183]

7.5 × 10¹⁴ Hz is the highest frequency of visible light when wavelengths of visible light range from 400 nm to 700 nm.

The distance a wave travels in one unit of time is known as the wave speed (v).Taking into account that the wave travels one wavelength in one interval,

v=λ/T

Given that T = 1/f, we can write the equation above as,

V = f λ

Given data:

Minimum wavelength of visible light = 400 nm = 4 × 10⁻⁷ m

Speed of light = 3 × 10⁸ m/s

Frequency = c/λ = 3 × 10⁸ / 4 × 10⁻⁷

= 7.5 × 10¹⁴ Hz

To learn more about Frequency: brainly.com/question/16200748

#SPJ4

4 0
1 year ago
Plz help me I’m a desperate little boy
Neporo4naja [7]

It is the first one. But if you have this question you are not a little boy

5 0
3 years ago
The illuminance due to a 60.0-w lightbulb at 3.0m is 9.35 lx. What is the total luminous flux of the bulb
Furkat [3]
The equation for luminous flux is given as P = 4\pir^{2}E
where P is the luminous flux, r is the distance and E is the illumination. The unit for P is lumen, E is lux and r is in meters. Substituting the given to the equation:

P = 4\pir^{2}E 

P= 4\pi(3)^{2}(9.35) = 1057.46 lumens (lm)

The total luminous flux is equal to 1057.46 lumens (lm).
3 0
3 years ago
A 440-g cylinder of brass is heated to 97.0 degree Celsius and placed in a 2 points
nydimaria [60]

Answer:

Specific heat of brass is 0.40 J g⁻¹ °C⁻¹ .

Explanation:

Given :

Mass of brass, m₁ = 440 g

Temperature of brass, T₁ = 97° C

Mass of water, m₂ = 350 g

Temperature of water, T₂ = 23° C

Specific heat of water, C₂ = 4.18 J g⁻¹ °C⁻¹

Equilibrium temperature, T = 31° C

Let C₁ be the specific heat of brass.

Heat loss by brass = Heat gain by water

m₁ x C₁ x ( T₁ -T ) = m₂ x C₂ x ( T - T₁ )

Substitute the suitable values in above equation.

440 x C₁ x (97 - 31) = 350 x 4.18 x (31 - 23)

C₁ = \frac{11704}{29040}

C₁ = 0.40 J g⁻¹ °C⁻¹

4 0
3 years ago
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