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krek1111 [17]
3 years ago
15

Compare an electrically neutral atom of hydrogen and an isotope of hydrogen.

Chemistry
1 answer:
Tju [1.3M]3 years ago
7 0

In comparison, a neutral hydrogen and an isotope of hydrogen have same chemical properties because o having the same number of protons and electrons, However, they have different number of neutrons which gives them their mass number. The difference in mass number gives the two isotope their mass related properties. For instance, a hydrogen isotope with an extra neutron will be much heavier than the neutral hydrogen.

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Give the expression for the solubility product constant for baf2.
svetoff [14.1K]

<span>Solubility product constant (Ksp) is </span>applied to the saturated ionic solutions<span> which are in equilibrium with its solid form. The solid is partially dissociated into its ions.</span><span>

For the BaF, the dissociation as follows;
BaF</span>₂(s) ⇄ Ba²⁺(aq) + 2F⁻(aq)

<span>
Hence,
        Ksp = [Ba</span>²⁺(aq)] [F⁻(aq)]²

3 0
3 years ago
2Fe + 3Cl2 → 2FeCl3 which of the following options gives the correct reactant ratio?
Mademuasel [1]

<u>Answer:</u> The reactant ratio in the given chemical equation will be: Fe:Cl_2=2:3

<u>Explanation:</u>

Mole ratio is defined as the ratio of the amount of moles of two substances that are participating in a chemical reaction.

In the given chemical equation:

2Fe+3Cl_2\rightarrow 2FeCl_3

The reactants are Fe and Cl_2 and the product is FeCl_3

The mole ratio is basically the stoichiometric ratio of the chemical compounds taking part in a chemical reaction.

The mole ratio of reactants is stoichiometric ratio of Fe and Cl_2, which is:

Fe:Cl_2=2:3

Hence, the reactant ratio in the given chemical equation will be: Fe:Cl_2=2:3

6 0
2 years ago
A student is performing an experiment to study thermodynamics. The student mixes citric acid and sodium bicarbonate in a calorim
seraphim [82]

Explanation :

In thermodynamics, a system is region or part of space which is being studied and observed while the surrounding is the region or space around the system which interacts with the system.

Here in the experiment ,system which is observed is reaction or changes when citric acid and sodium bicarbonate are mixed together. And the mixing is carried out in the calorimeter which serves as a surrounding around the system.

The reason behind the using the calorimeter is measure the energy change occurring during the reaction.

5 0
3 years ago
(b) The conductivity of a 0.01 mol dm–3 solution of a monobasic organic acid in water is 5.07 × 10–2 S m–1. If the molar conduct
Zarrin [17]

Explanation:

The given data is as follows.

   \Lambda^{o}_{m}(NaCl) = 1.264 \times 10^{-2}

   \Lambda^{o}_{m}(H-O=C-ONO) = 1.046 \times 10^{-2}

   \Lambda^{o}_{m}(HCl) = 4.261 \times 10^{-2}

Conductivity of monobasic acid is 5.07 \times 10^{-2} S m^{-1}

     Concentration = 0.01 mol/dm^{3}

Therefore, molar conductivity (\Lambda_{m}) of monobasic acid is calculated as follows.

                 \Lambda_{m} = \frac{conductivity}{concentration}

                                  = \frac{5.07 \times 10^{-2} S m^{-1}}{0.01 mol/dm^{3}}

                                 = \frac{5.07 \times 10^{-2} S m^{-1}}{0.01 mol \times 10^{3}}

                                 = 5.07 \times 10^{-3} S m^{2} mol^{-1}

Also, \Lambda^{o}_{m} = \Lambda^{o}_{m}_{(HCl)} + \Lambda^{o}_{m}_{(H-O=C-ONO)} - \Lambda^{o}_{m}_{(NaCl)}

                            = 4.261 \times 10^{-2} + 1.046 \times 10^{-2} - 1.264 \times 10^{-2}

                            = 4.043 \times 10^{-2} S m^{2} mol^{-1}

Relation between degree of dissociation and molar conductivity is as follows.

               \alpha = \frac{\Lambda_{m}}{\Lambda^{o}_{m}}

                             = \frac{5.07 \times 10^{-2} S m^{-1}}{4.043 \times 10^{-2} S m^{2} mol^{-1}}

                             = 0.1254

Whereas relation between acid dissociation constant and degree of dissociation is as follows.

                     K = \frac{c \times \alpha^{2}}{1 - \alpha}

Putting the values into the above formula we get the following.

                     K = \frac{c \times \alpha^{2}}{1 - \alpha}

                        = \frac{0.01 \times (0.1254)^{2}}{1 - 0.1254}

                        = 0.017973 \times 10^{-2}

                       = 1.7973 \times 10^{-4}

Hence, the acid dissociation constant is 1.7973 \times 10^{-4}.

Also, relation between pK_{a} and K_{a} is as follows.

                 pK_{a} = -log K_{a}

                              = -log (1.7973 \times 10^{-4})

                              = 3.7454

Therefore, value of pK_{a} is 3.7454.

                             

3 0
2 years ago
4. What is the main hydrocarbon component of natural gas? A. ethane
KIM [24]

Answer:

Q.4) C. Methane

Q.7) A. False

Q.8) A. True

7 0
2 years ago
Read 2 more answers
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