85 N - 40 N = 45 N
And depending on direction the greater force is being pulled towards
Answer:
It's 1.0000042 times longer in summer than in winter. It represents a 1.6 centimeters difference between seasons.
Explanation:
The linear coefficient of thermal expansion for steel is about 
. From the equation of linear thermal expansion, we have:
Taking the winter day as the initial, and the summer day as the final, we can take the relationship between them:
![L_{summer}=L_{winter}[1+(1.2*10^{-7}\°C^{-1})(30\°C+5\°C)]\\\\L_{summer}=(1.0000042)L_{winter}](https://tex.z-dn.net/?f=L_%7Bsummer%7D%3DL_%7Bwinter%7D%5B1%2B%281.2%2A10%5E%7B-7%7D%5C%C2%B0C%5E%7B-1%7D%29%2830%5C%C2%B0C%2B5%5C%C2%B0C%29%5D%5C%5C%5C%5CL_%7Bsummer%7D%3D%281.0000042%29L_%7Bwinter%7D)
It means that the bridge is 1.0000042 times longer in summer than in winter. If we multiply it by the length of the bridge, we obtain that the difference is of about 1.6 centimeters between the two seasons.
1) 211m/s
2)240<span>°
3)759,600m or 759.6 km</span>
Answer:
1 eV
Explanation:
Given:
Work function, ∅ = 2.00 eV
Kinetic energy of the ejected of the electron, K.E = 4.0 eV
Now,
using the photoelectric equation
, we have
Energy of the photon (E) = ∅ + K.E
also,
E = hc/λ
where, h is plank's constant
c is the speed of the light
λ is the wavelength
thus, we have
hc/λ = 2 + 4 = 6 eV
Energy of photon = 6eV
Now,
for the second case
λ' = 2λ
when Wavelength is doubled , E is halved
thus,
E' = hc/λ'
or
E' = hc/2λ
or
E' = E/2 = 6/2 = 3 eV
also,
E' = ∅ + KE
'
thus on substituting the values,
3 = 2 + KE'
or
KE' = 1 eV
Hence, the maximum kinetic energy for the second case is 1 eV
