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natima [27]
3 years ago
11

Line d represents water. if the atmospheric pressure in a flask is lowered to 70 kpa, water would boil at what temperature?

Physics
1 answer:
sp2606 [1]3 years ago
5 0
The diagram is in the picture attached.
Options are:
A) 32 °C
B) 70 °C
C) 92 °C
D) 100 °C

In order to find the value required, you need to look at the diagram and follow these steps:
1) search for the value of 70 kPa on the y-axis;
2) move on a horizontal line towards the right until you reach the line D;
3) move on a vertical line down, towards the x-axis;
4) read at what value of °C you are at.

Doing so, you can see that you are at a value a little bit above 90 °C (see picture).

Hence, the correct answer is C) 92°C.

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A load of mass 5kg is raised through a height of 2m. (g=10mls)​
s2008m [1.1K]

The gain in gravitational potential energy of the mass = 100 kg m^2 / s^2.

<u>Explanation:</u>

Gravitational potential energy is an energy in which an object possesses because of its position in a gravitational field. The most common use of gravitational potential energy is for an object near the Earth's surface where the gravitational acceleration can be assumed to be constant at about 9.8 m/s2.

The formula for the gravitational potential energy is the product of mass, gravity, and height.

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3 years ago
Sugar is made of carbon, hydrogen, and oxygen atoms.Sugar is
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Answer:

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No, ya que, es una mezcla homogénea, es decir,  sus elementos están muy unidos mas no combinados de manera química, es posible separarlos pero con mucha dificultad, por tanto, es imposible diferenciarlos a simple vista. Se sabe que están distribuidos de manera uniforme, su estado es conocido como solución o disolución, tal como es el caso del azúcar.

Explanation:

I hope my answer serves you and that it is to your liking please give me cornita: 3

4 0
4 years ago
When a battery, a resistor, a switch, and an inductor form a circuit and the switch is closed, the inductor acts to oppose the c
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Answer:

The time constant becomes twice.

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Time constant of the L-R circuit is given as

T = \frac{L}{R}\\

T_{1} = initial time constant of the L-R circuit = T

T_{2} = final time constant of the L-R circuit

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L_{2} = Initial inductance of the inductor =  2L

For the same resistance, the time constant depend directly on the inductance, hence

\frac{T_{1}}{T_{2}} = \frac{L_{1}}{L_{2}}\\\frac{T}{T_{2}} = \frac{L}{2L}\\\frac{T}{T_{2}} = \frac{1}{2}\\T_{2} = 2T

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Answer:

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Explanation:

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