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natima [27]
3 years ago
11

Line d represents water. if the atmospheric pressure in a flask is lowered to 70 kpa, water would boil at what temperature?

Physics
1 answer:
sp2606 [1]3 years ago
5 0
The diagram is in the picture attached.
Options are:
A) 32 °C
B) 70 °C
C) 92 °C
D) 100 °C

In order to find the value required, you need to look at the diagram and follow these steps:
1) search for the value of 70 kPa on the y-axis;
2) move on a horizontal line towards the right until you reach the line D;
3) move on a vertical line down, towards the x-axis;
4) read at what value of °C you are at.

Doing so, you can see that you are at a value a little bit above 90 °C (see picture).

Hence, the correct answer is C) 92°C.

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A car is moving down the street at 53km/h. A child suddenly runs into the street. If it takes the driver 0.75 sec to react and a
BARSIC [14]

Answer:

11.04m

Explanation:

Convert kilometers to meters: 53km/h x 1000 = 53,000m/h

Convert hours to seconds: 53m/h / 3600 =14.72m/s

14.72 (.75) = 11.04

8 0
2 years ago
Your friend's car is stuck in the snow. You push very hard and become very 1 tired but the car won't move. Did you do work?
crimeas [40]

Answer:

Yes you  worked

Explanation:

You may have not seen a good outcome but you did put effort in.

7 0
3 years ago
During fuel burn, the vertically launched Terrier-Sandhawk rocket had an acceleration of 300 m/s2 (about 30 times free-fall acce
givi [52]

The equation that we can use in this case is:

y = v0 t + 0.5 a t^2

where, y is the height, v0 is initial velocity = 0, t is time, a is acceleration so that:

y = 0 + 0.5 * (300 m/s^2) * (7 s)^2

<span>y = 7350 m</span>

5 0
2 years ago
A charge of 63.0 nC is located at a distance of 3.40 cm from a charge of -47.0 nC. What are the x- and y-components of the elect
Serjik [45]

Answer:

Ep_x = 288.97*10^3\frac{N}{C}

Ep_y = 2770.6*10^3\frac{N}{C}

Explanation:

Conceptual analysis

The electric field at a point P due to a point charge is calculated as follows:

E = k*q/r²

E: Electric field in N/C

q: charge in Newtons (N)

k: electric constant in N*m²/C²

r: distance from charge q to point P in meters (m)

The electric field at a point P due to several point charges is the vector sum of the electric field due to individual charges.

Equivalences

1nC= 10⁻⁹ C

1cm= 10⁻² m

Graphic attached

The attached graph shows the field due to the charges:

Ep₁: Total field at point P due to charge q₁. As the charge is positive ,the field leaves the charge.

Ep₂: Total field at point P due to charge q₂. As the charge is negative, the field enters the charge.

Known data

q₁ = 63 nC = 63×10⁻⁹ C

q₂ = -47 nC = -47×10⁻⁹ C

k = 8.99*10⁹ N×m²/C²

d₁ = 1.4cm = 1.4×10⁻² m

d₂ = 3.4cm = 3.4×10⁻² m

Calculation of r and β

r=\sqrt{d_1^2 + d_2^2} = \sqrt{(1.4*10^{-2})^2 + (3.4*10^{-2})^2} = 3.677*10^{-2}m

\beta = tan^{-1}(\frac{d_1}{d_2}) = tan^{-1}(\frac{1.4}{3.4}) = 22.38^o

Problem development

Ep: Total field at point P due to charges q₁ and q₂.

Ep = Ep_x i + Ep_y j

Ep₁ₓ = 0

Ep_{2x}=\frac{-k*q_2*Cos\beta}{r^2}=\frac{8.99*10^9*47*10^{-9}*Cos(22.38)}{(3.677*10^{-2})^2}=288.97*10^3\frac{N}{C}

Ep_{1y}=\frac{-k*q_1}{d_1^2}=\frac{8.99*10^9*63*10^{-9}}{(1.4*10^{-2})^2}=2889.6*10^3\frac{N}{C}

Ep_{2y}=\frac{-k*q_2*Sen\beta}{r^2}=\frac{-8.99*10^9*47*10^{-9}*Sen(22.38)}{(3.677*10^{-2})^2}=-119*10^3\frac{N}{C}

Calculation of the electric field components at point P

Ep_x = Ep_{1x} + Ep_{2x} = 0 + 288.97*10^3 = 288.97*10^3\frac{N}{C}

Ep_y = Ep_{1y} + Ep_{2y} = 2889.6*10^3 - 119*10^3 = 2770.6*10^3\frac{N}{C}

6 0
3 years ago
A 7000-kg plane is launched from an aircraft carrier in 2.0 seconds
ExtremeBDS [4]

The acceleration and velocity of the plane is 78.57 m/s² and 157.14 m/s respectively

To calculate the acceleration of the plane, we use the formula below.

<h3>Formula:</h3>
  • a = F/m..................... Equation 1

Where:

  • a = Acceleration of the plane
  • F = Force applied to the plane
  • m = mass of the plane.

From the question,

Given:

  • F = 550000 N
  • m = 7000 kg

Substitute these values into equation 1

  • a = 550000/7000
  • a = 78.57 m/s²

To calculate the velocity, we use the formula below.

  • v = u+at............. Equation 2

Where:

  • v = Final velocity
  • u = initial velocity
  • a = acceleration
  • t = time.

From the question,

Given:

  • u = 0 m/s
  • a = 78.57 m/s
  • t = 2.0 seconds

Substitute these values into equation 2

  • v = 0+2(78.57)
  • v = 157.14 m/s

Hence, The acceleration and velocity of the plane is 78.57 m/s² and 157.14 m/s respectively.
Learn more about acceleration here: brainly.com/question/460763

5 0
1 year ago
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