Answer:
pKb = 10.96
Explanation:
Tartaric acid is a dyprotic acid. It reacts to water like this:
H₂Tart + H₂O ⇄ H₃O⁺ + HTart⁻ Ka1
HTart⁻ + H₂O ⇄ H₃O⁺ + Tart⁻² Ka2
When we anaylse the base, we have
Tart⁻² + H₂O ⇄ OH⁻ + HTart⁻ Kb1
HTart⁻ + H₂O ⇄ OH⁻ + H₂Tart Kb2
Remember that Ka1 . Kb2 = Kw, plus pKa1 + pKb2 = 14
Kb2 = Kw / Ka1 → 1×10⁻¹⁴ / 9.20×10⁻⁴ = 1.08×10⁻¹¹
so pKb = - log Kb2 → - log 1.08×10⁻¹¹ = 10.96
Answer: The freezing point of the solution is
The boiling point of the solution is
Explanation:
Depression in freezing point is given by:
= Depression in freezing point
i= vant hoff factor = 3 (for electrolyte undergoing complete dissociation, i is equal to the number of ions produced)
= freezing point constant =
m= molality = 2.40 m
Thus the freezing point of the solution is
Elevation in boiling point is given by:
= Elevation in boiling point
i= vant hoff factor = 3 (number of ions an electrolyte produce on complete dissociation)
= freezing point constant =
m= molality
Thus the boiling point of the solution is
Just simply... they both are energy.
Use a bow and arrow as an example:
When you pull back an arrow, potential energy or PE is stored in the string and the limbs of the bow.
When you release the the arrow, energy is being transferred from the bow to the arrow. The arrow now has kinetic energy or KE, this means that the energy is being used by the arrow.