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3 years ago

Suppose the initial kinetic energy and final potential energy in an experiment are both zero. What can you conclude?

Physics

2 answers:

faltersainse [42]3 years ago

4 0

At the beginning it is not moving and at the end it is on the ground or the bottom of a hill.

puteri [66]3 years ago

3 0

Answer:

That an item is neither moving nor staying still in a position that is building up energy.

Explanation:

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KatRina [158]

Answer:

i would think the first two, but i cant be sure.

Explanation:

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3 years ago

Guys please help me out I’ll give extra points

zvonat [6]

Answer: h = 3.34 m

Explanation:

If the hat is thrown straight up, then at its highest point it has no motion and no kinetic energy. All energy is potential energy

PE = mgh

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3 years ago

An embolus can cause which of the following?

QveST [7]

I think it’s C. Stroke if not then D

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3 years ago

When you irradiate a metal with light of wavelength 433 nm in an investigation of the photoelectric effect, you discover that a

sergij07 [2.7K]

Answer:

The right solution is:

(a) 2.87 eV

(b) 1.4375 eV

Explanation:

Given:

Wavelength,

= 433 nm

Potential difference,

= 1.43 V

Now,

(a)

The energy of photon will be:

E = $\frac{6.626\times 10^{-34}\times 3\times 10^8}{433\times 10^{-9}}$

= $4.59\times 10^{-19} \ J$

or,

= $\frac{4.59\times 10^{-19}}{1.6\times 10^{-19}}$

= $2.87 \ eV$

(b)

As we know,

⇒ $Vq=\frac{hc}{\lambda}-\Phi_0$

By substituting the values, we get

⇒ $1.43\times 1.6\times 10^{19}=\frac{6.626\times 10^{-34}\times 3\times 10^8}{433\times 10^{-9}}-\Phi_0$

⇒ $\Phi_0=2.3\times 10^{-19} \ J$

or,

⇒ $=\frac{2.3\times 10^{-19}}{1.6\times 10^{-19}}$

⇒ $=1.4375 \ eV$

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3 years ago

How do u get rid of a hacker? plz help my friend needs this

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IP address then call the cops

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3 years ago

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