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Dvinal [7]
3 years ago
6

Translate into an inequality:

Mathematics
1 answer:
qwelly [4]3 years ago
8 0

Answer: x < 2/3

Step-by-step explanation:

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Tadeo Volunteered at the library six times as many hours over the weekend as Dylan. Together they volunteer at a total of 14 hou
LuckyWell [14K]

Answer:

<em>Tadeo Volunteered for 12 hours while Dylan volunteered for 2 hours</em>

Step-by-step explanation:

Let the total number of hours Tadeo volunteered be x

Let the total number of hours Dylan volunteered be y

If together they volunteer at a total of 14 hours, then;

x + y = 14 ...... 1

If<em> </em>Tadeo Volunteered at the library six times as many hours over the weekend as Dylan, then;

x = 6y

Substitute x = 6y into 1;

6y + y = 14

7y = 14

y = 14/7

y = 2

Since x = 6y

x = 6(2)

x = 12

<em>Hence Tadeo Volunteered for 12 hours while Dylan volunteered for 2 hours</em>

4 0
3 years ago
32i-4+2=6-42i-3 help
Dmitrij [34]
15i would be your best answer
8 0
2 years ago
Two walls have the same area. The first wall is in the shape of a square and has a height
STatiana [176]

Answer:

27 feet

Step-by-step explanation:

Two walls have same area

Area of first wall(square) = 18*18 = 324

Area of second wall = 12 * x = 324

324/12 = 27

27 feet

7 0
3 years ago
I could use a little help with this one. i'm rusty.<br> -3(x+2)-7 = 5x + 7
Pie

Answer:

-3(x+2)-7 = 5x + 7

-3x - 6 - 7 = 5x + 7

-3x - 13 = 5x + 7

-20 = 8x

x = -2.5

7 0
3 years ago
Read 2 more answers
the sum of the first nine terms of an arithmetic series is 162, and the sum of the first 12 terms is 288. Determine the first fi
Natali5045456 [20]

Answer:

\boxed{\pink{\tt \leadsto Sum \ of \ first \ five \ terms \ is \ 50 . }}

Step-by-step explanation:

Given that , the sum of the first nine terms of an arithmetic series is 162 and the sum of the first 12 terms is 288.

\boxed{\red{\bf \bigg\lgroup For \ answer \ refer \ to \ attachment \bigg\rgroup  }}

<h3><u>Related</u><u> </u><u>Infor</u><u>mation</u><u> </u><u>:</u><u>-</u><u> </u></h3>

• The sum of n terms of an AP is

\boxed{\orange{\sf S_n = \dfrac{n}{2}[2a+(n-1)d] }}

• nth term of an AP is given by ,

\boxed{\blue{\sf T_n = a+(n-1)d }}

8 0
2 years ago
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